Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 28)
28.
The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:
Answer: Option
Explanation:
Let the numbers be 2x and 3x.
Then, their L.C.M. = 6x.
So, 6x = 48 or x = 8.
The numbers are 16 and 24.
Hence, required sum = (16 + 24) = 40.
Discussion:
19 comments Page 1 of 2.
MENA said:
2 years ago
@ALL.
48/2 = 24,
48/3 = 16,
Then, 24+16 = 40.
Thanks!
48/2 = 24,
48/3 = 16,
Then, 24+16 = 40.
Thanks!
(11)
Tanya said:
2 years ago
Let the numbers be equal to= k.
the ratio is given as= 2:3.
1st num = 2k.
2nd num = 3k.
Now find their lcm as we find for every number so factors will be= 2 x3 x k =6k.
but in question, the lcm of numbers is given as 48.
that is LCM(of 2k,3k)= 48.
but we found that LCM is 6k.
Thus,
48 = 6k.
k = 48/6,
k = 8.
Now put the value of k for 1st num and second num to find the numbers and we get:-
1st num = 2(8) = 16,
2nd num = 3(8) = 24.
now sum = 16 + 24 = 40.
Hence 40 is the answer.
the ratio is given as= 2:3.
1st num = 2k.
2nd num = 3k.
Now find their lcm as we find for every number so factors will be= 2 x3 x k =6k.
but in question, the lcm of numbers is given as 48.
that is LCM(of 2k,3k)= 48.
but we found that LCM is 6k.
Thus,
48 = 6k.
k = 48/6,
k = 8.
Now put the value of k for 1st num and second num to find the numbers and we get:-
1st num = 2(8) = 16,
2nd num = 3(8) = 24.
now sum = 16 + 24 = 40.
Hence 40 is the answer.
(3)
Anurag said:
3 years ago
By Heat and trail method:
48/2 = 24
48/3 = 16.
24 and 16 are those two numbers and sum of these two number is 24+16 = 40.
By general Rule -:
1st number * 2nd number = HCF * LCM.
we have LCM = 48 ;
LCM = ( 1st no * 2nd no)/ HCF.
let HCF = X.
Then 1st number = 2x and,
2nd number = 3x.
so,
48 = (2X * 3X)/X.
(6X^2 ) / X = 48
Then, ,6X = 48,
X = 48/6 = 8.
So, the first number is 2X = 2 * 8 = 16
second number is 3X = 3 * 8 = 24.
Sum of those number is 16 + 24 = 40.
Other method:
We have LCM = 48.
let these two numbers are 2X and 3X.
L.C.M. of 2X and 3X is 6X.
If you do LCM we got X,2,3 multiple of these number is 6X.
So,
6X = 48,
X = 48/6 = 8.
The numbers are 16 and 24.
sum is 40.
That's all.
Thanks
48/2 = 24
48/3 = 16.
24 and 16 are those two numbers and sum of these two number is 24+16 = 40.
By general Rule -:
1st number * 2nd number = HCF * LCM.
we have LCM = 48 ;
LCM = ( 1st no * 2nd no)/ HCF.
let HCF = X.
Then 1st number = 2x and,
2nd number = 3x.
so,
48 = (2X * 3X)/X.
(6X^2 ) / X = 48
Then, ,6X = 48,
X = 48/6 = 8.
So, the first number is 2X = 2 * 8 = 16
second number is 3X = 3 * 8 = 24.
Sum of those number is 16 + 24 = 40.
Other method:
We have LCM = 48.
let these two numbers are 2X and 3X.
L.C.M. of 2X and 3X is 6X.
If you do LCM we got X,2,3 multiple of these number is 6X.
So,
6X = 48,
X = 48/6 = 8.
The numbers are 16 and 24.
sum is 40.
That's all.
Thanks
(1)
Aman said:
3 years ago
How the LCM of 2x, 3x = 6x? Explain please.
(1)
LeGeNd Aryan said:
3 years ago
Best method;
Ratio = 2:3.
So, let the numbers be 2x and 3x respectively.
Sum = 2x + 3x = 5x.
=> Sum is MULTIPLE OF 5.
There is only one option which is a MULTIPLE of 5. So 40 is the answer.
Ratio = 2:3.
So, let the numbers be 2x and 3x respectively.
Sum = 2x + 3x = 5x.
=> Sum is MULTIPLE OF 5.
There is only one option which is a MULTIPLE of 5. So 40 is the answer.
(4)
Nikhil said:
4 years ago
Let say we need to find LCM of 2x and 3x;
So.
--- 2x 3x
x | 2 | 3
2 | 1 | 3
3 | 1 | 1
multiply 2 * 3 * x = 6x.
So.
--- 2x 3x
x | 2 | 3
2 | 1 | 3
3 | 1 | 1
multiply 2 * 3 * x = 6x.
(4)
Tanmay Punse said:
7 years ago
@Ambi.
It's so simple,
Then x of HCF and x in 6x^2 gets cancelled.
And hence 6x is remained.
It's so simple,
Then x of HCF and x in 6x^2 gets cancelled.
And hence 6x is remained.
Prem said:
8 years ago
Very simple way, 2:3 means sum is always a multiple of 5. Here only multiple of 5 is 40.
Rakesh.h said:
9 years ago
Simple way.
48/2 = 24.
48/3 = 16.
24 + 16 = 40.
48/2 = 24.
48/3 = 16.
24 + 16 = 40.
(3)
V!cky said:
10 years ago
Product of two number = Product of HCF and LCM.
Here we go to solve problem:
48 = x*{3*2}.
48/6 = x.
x = 8.
3x:2x = 3*8:2*8.
1st number 24:2nd number 16.
= 40.
Here we go to solve problem:
48 = x*{3*2}.
48/6 = x.
x = 8.
3x:2x = 3*8:2*8.
1st number 24:2nd number 16.
= 40.
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers