Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 28)
28.
The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:
28
32
40
64
Answer: Option
Explanation:

Let the numbers be 2x and 3x.

Then, their L.C.M. = 6x.

So, 6x = 48 or x = 8.

The numbers are 16 and 24.

Hence, required sum = (16 + 24) = 40.

Discussion:
19 comments Page 1 of 2.

Mythili said:   2 decades ago
How 6x came? please explain.

Uma Upadhyay said:   1 decade ago
@ Mythlili

The LCM of 2 &3 is 6 taking X as common factor, the LCM of 2x & 3x will 6X.

Uttam said:   1 decade ago
Product of two numbers = Product of their H.C.F. and L.C.M.
consider HCF as X,
so,
two nos are 2X and 3X
then,
2X*3X=X*48.
solving for X
X=48/6
we get
X=8
so the nos,16,24
and ans 40.

Ritu said:   1 decade ago
How came 16 and 24 ?

Gufran said:   1 decade ago
Already uttam find....X=8.
and we have 2X&3X=2*8=16 & 3*8=24

Arif said:   1 decade ago
Here you do 2x and 3x. The sum of two. So 2x*3x=6x2. Why 6x?

Ambi said:   1 decade ago
Why its not X square? and only X. While solving mathematically it should be x square?

Roma said:   1 decade ago
It's so simple.

Let h.c.f means multiply and l.c.m means divide.

So 2/48 = 1/24.
And 3/48 = 1/16.

Let take additon of 16+24 = 40.

Sanjay kiran said:   1 decade ago
How 16 and 24 got? Please explain.

V!cky said:   10 years ago
Product of two number = Product of HCF and LCM.

Here we go to solve problem:

48 = x*{3*2}.
48/6 = x.
x = 8.

3x:2x = 3*8:2*8.

1st number 24:2nd number 16.

= 40.
(1)


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