Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 28)
28.
The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:
Answer: Option
Explanation:
Let the numbers be 2x and 3x.
Then, their L.C.M. = 6x.
So, 6x = 48 or x = 8.
The numbers are 16 and 24.
Hence, required sum = (16 + 24) = 40.
Discussion:
19 comments Page 2 of 2.
Roma said:
1 decade ago
It's so simple.
Let h.c.f means multiply and l.c.m means divide.
So 2/48 = 1/24.
And 3/48 = 1/16.
Let take additon of 16+24 = 40.
Let h.c.f means multiply and l.c.m means divide.
So 2/48 = 1/24.
And 3/48 = 1/16.
Let take additon of 16+24 = 40.
Prem said:
8 years ago
Very simple way, 2:3 means sum is always a multiple of 5. Here only multiple of 5 is 40.
Tanmay Punse said:
7 years ago
@Ambi.
It's so simple,
Then x of HCF and x in 6x^2 gets cancelled.
And hence 6x is remained.
It's so simple,
Then x of HCF and x in 6x^2 gets cancelled.
And hence 6x is remained.
Ambi said:
1 decade ago
Why its not X square? and only X. While solving mathematically it should be x square?
Arif said:
1 decade ago
Here you do 2x and 3x. The sum of two. So 2x*3x=6x2. Why 6x?
Gufran said:
1 decade ago
Already uttam find....X=8.
and we have 2X&3X=2*8=16 & 3*8=24
and we have 2X&3X=2*8=16 & 3*8=24
Ritu said:
1 decade ago
How came 16 and 24 ?
Uttam said:
1 decade ago
Product of two numbers = Product of their H.C.F. and L.C.M.
consider HCF as X,
so,
two nos are 2X and 3X
then,
2X*3X=X*48.
solving for X
X=48/6
we get
X=8
so the nos,16,24
and ans 40.
consider HCF as X,
so,
two nos are 2X and 3X
then,
2X*3X=X*48.
solving for X
X=48/6
we get
X=8
so the nos,16,24
and ans 40.
Uma Upadhyay said:
1 decade ago
@ Mythlili
The LCM of 2 &3 is 6 taking X as common factor, the LCM of 2x & 3x will 6X.
The LCM of 2 &3 is 6 taking X as common factor, the LCM of 2x & 3x will 6X.
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