Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 6)
6.
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
Answer: Option
Explanation:
Let the numbers be 37a and 37b.
Then, 37a x 37b = 4107
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
Greater number = 111.
Discussion:
76 comments Page 6 of 8.
Bijip said:
2 years ago
Why we will take co-prime here? Please explain me.
(10)
MAHESH said:
1 decade ago
X*Y = 4107.
X*37 = 4107.
X = 4107/37.
X = 111.
X*37 = 4107.
X = 4107/37.
X = 111.
Sonu Gurjar said:
4 months ago
Formula:
4107 = 37 * lcm,
Lcm = 4107/37 = 111.
4107 = 37 * lcm,
Lcm = 4107/37 = 111.
(13)
Durga said:
1 decade ago
But how we will know 37 is the H.C.F first only.
Sangeetha said:
9 years ago
How will we decide 111 is the largest number?
(1)
Mayur said:
4 years ago
Simple;
HCF*LCM = PRODUCT.
37 * 111 = 4107.
HCF*LCM = PRODUCT.
37 * 111 = 4107.
(38)
Pannu said:
1 decade ago
37a*37b=4107
1369ab=4107
ab=4107/1369
ab=3
1369ab=4107
ab=4107/1369
ab=3
(1)
Sanjivani said:
1 decade ago
Co prime means not get co-prime (1, 3).
(1)
Anand said:
1 decade ago
Simply multiply the value 37*111=4107
Vani said:
1 decade ago
Can LCM always be the greatest no.?
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