Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 6)

Problems on H.C.F and L.C.M

The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:

101

107

111

185

Answer: Option

Explanation:

Let the numbers be 37a and 37b.

Then, 37a x 37b = 4107

ab = 3.

Now, co-primes with product 3 are (1, 3).

So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).

Greater number = 111.

Discussion:

76 comments Page 8 of 8.

Arun said: 8 years ago

Thank you all.

Rahul said: 1 decade ago

Thanks Pannu.

Priya.E said: 8 years ago

Thnks @Pannu.

111 said: 1 decade ago

Thanks anand

Hhmnmb said: 1 decade ago

Thanks Anand

Jaz said: 1 decade ago

Thanks raj.

(1)

Post your comments here:

Quick links

Quantitative Aptitude

Verbal (English)

Reasoning

Programming

Interview

Placement Papers