Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 6)
6.
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
Answer: Option
Explanation:
Let the numbers be 37a and 37b.
Then, 37a x 37b = 4107
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
Greater number = 111.
Discussion:
76 comments Page 7 of 8.
Srivani said:
4 years ago
How you get ab=3? please explain.
(10)
Frio said:
1 year ago
Thanks all for the explanation.
(3)
Arif said:
1 decade ago
But in case of smaller number?
Muthusamy said:
1 decade ago
Thanks raju and thulasi.
Gopi said:
4 years ago
37 * x = 4107.
x = 111.
x = 111.
(7)
Roy said:
1 decade ago
What is co-prime nos?
Nilay said:
4 years ago
Thank you @Shilpa.
(1)
Marisankar said:
6 years ago
What is co-prime?
Omprakash said:
3 years ago
Thanks, everyone.
(6)
Rakesh said:
1 decade ago
How you got ab=3?
(1)
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