Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 6)
6.
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
Answer: Option
Explanation:
Let the numbers be 37a and 37b.
Then, 37a x 37b = 4107
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
Greater number = 111.
Discussion:
76 comments Page 5 of 8.
Rups said:
1 decade ago
H.C.F*L.C.M = a*b.
37*L.C.M = 4107.
L.C.M = 4107/37.
L.C.M = 111.
37*L.C.M = 4107.
L.C.M = 4107/37.
L.C.M = 111.
Nikita said:
1 decade ago
Please explain the given evaluation properly. By co-prime method only.
Mehar said:
1 decade ago
Easy way to get ans:divide the product with H.C.F
-->4107/37=111;
-->4107/37=111;
Shoaib nadaf said:
6 years ago
Hcf x lcm = Product .
37 x X = 4107.
X = 4107/37 = 111 answer.
37 x X = 4107.
X = 4107/37 = 111 answer.
PVNARASIMHARAO said:
1 decade ago
L.C.M * H.C.F=FIRSTNUMEBR * SECONDNUMBER
IF THEY ARE COPRIMES
IF THEY ARE COPRIMES
Raj said:
1 decade ago
Simple method:
LCM=product of co primes/HCF
=>4107/37=111
LCM=product of co primes/HCF
=>4107/37=111
(1)
Thulsi said:
1 decade ago
Best method by verification.
Divide 4107 by 37 we get 111.
Divide 4107 by 37 we get 111.
Ramesh M said:
9 years ago
Same doubt for me @Sangeetha.
Please can anyone help us.
Please can anyone help us.
Prakruthi said:
1 decade ago
a*b = HCF*LCM;
4107 = 37*LCM;
LCM = 4107/37;
LCM = 111;
4107 = 37*LCM;
LCM = 4107/37;
LCM = 111;
Jyoti said:
1 decade ago
Simply divide the product with H.C.F
i.e 4107/37=111
i.e 4107/37=111
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