Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 6)
6.
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
Answer: Option
Explanation:
Let the numbers be 37a and 37b.
Then, 37a x 37b = 4107
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
Greater number = 111.
Discussion:
76 comments Page 4 of 8.
Abitha said:
7 years ago
Here for ab=3, its possibilities are (1, 2) & (2, 1) Only right?
Please, anyone, help me.
Please, anyone, help me.
Anirudh said:
9 years ago
1250 is the product of x and y. What is the HCF of x and y?
Solve and explain the solution.
Solve and explain the solution.
Vinay said:
1 decade ago
It is not essential that LCM will always be greater number
@ ravi
your explanation are good
@ ravi
your explanation are good
Mouni said:
4 years ago
HCF=37
The product of two no's=4107
37 * x = 4107, where x=greatest no
x = 4107%37 = 111.
The product of two no's=4107
37 * x = 4107, where x=greatest no
x = 4107%37 = 111.
(4)
Priya said:
1 decade ago
This will work on co-primes. If two numbers are not coprimes then how should we find out ?
Nidhu said:
6 years ago
We know that;
H.C.F * L.C.M = product of two numbers.
37* x = 4107,
x=4107/37,
x = 111.
H.C.F * L.C.M = product of two numbers.
37* x = 4107,
x=4107/37,
x = 111.
Sandip said:
1 decade ago
We know that HCF*LCM = Product of two number.
So the other no is = 4107/37 = 111.
So the other no is = 4107/37 = 111.
Vijesh said:
1 decade ago
SIMPLE METHOD:
PRODUCT OF THE TWO NUMBERS = LCM*HCF.
4107 = 37*LCM.
LCM = 111.
PRODUCT OF THE TWO NUMBERS = LCM*HCF.
4107 = 37*LCM.
LCM = 111.
Aman Kaushik said:
1 decade ago
Just a very simple method.
Product of the two number/ HCF.
4107/37 = 111.
Product of the two number/ HCF.
4107/37 = 111.
MJani said:
1 decade ago
Explain any short method to solve this problem? Its too long of 4107/1369.
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