Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 6)
6.
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
Answer: Option
Explanation:
Let the numbers be 37a and 37b.
Then, 37a x 37b = 4107
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
Greater number = 111.
Discussion:
76 comments Page 3 of 8.
Raushan said:
9 years ago
In the any condition you can take, it is not only for co-prime. It will work for all.
And two numbers are said to be co-prime if the HCF is 1.
And two numbers are said to be co-prime if the HCF is 1.
Kajal said:
10 years ago
How we come to know that in this question we have to find LCM, in the question we have to find the greater number, reply as soon as possible?
OM SHANKAR PRASAD said:
9 years ago
@Anirudh.
Because we can make pair of (10*125) , (50*25), (250*5), (2*625), (1*1250), so HCF is varying, so I think more data need.
Because we can make pair of (10*125) , (50*25), (250*5), (2*625), (1*1250), so HCF is varying, so I think more data need.
Sushma said:
1 decade ago
Its simple let a * b = 4107 now 37 is common in both a and b so 37*some number(x)=4107 so solve this 37*x=4107 so 4107/37 =111.
Sai vamsi said:
6 years ago
x*y = 4107.
Hcf of two nums is 37. So these two nums are divisible by 37.
37x*37y = 4107.
37(x*y) = 4107.
x*y = 4107/37 = 111.
Hcf of two nums is 37. So these two nums are divisible by 37.
37x*37y = 4107.
37(x*y) = 4107.
x*y = 4107/37 = 111.
Asif said:
8 years ago
How we come to know that in this question we have to find LCM, in the question we have to find the greater number? please.
Harwani Payal said:
6 years ago
Assume Two numbers p and q.
Multiply them with 37.
37p*37p.
Now, 37p*37p = 4107.
1369pq = 4107.
pq = 4107/1369.
pq = 3.
Multiply them with 37.
37p*37p.
Now, 37p*37p = 4107.
1369pq = 4107.
pq = 4107/1369.
pq = 3.
Mukesh said:
1 decade ago
HCF means greater number divisible. 37 is dividable by 1 and 37. Apart from this 37 is highest. So divide 4107/39=111.
Sachin said:
1 decade ago
Best method is to use the co primes as it in the given explanation.
4107/37=111, which is not the correct solution.
4107/37=111, which is not the correct solution.
MANJULADEVI K said:
3 years ago
The product of 2 number is 4107.
The HCF of these number is 37.
4107= 37 * a
4107/37 = a
Answer is 111.
The HCF of these number is 37.
4107= 37 * a
4107/37 = a
Answer is 111.
(82)
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