Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
2 times
1 times
2
3 times
4
3 times
Answer: Option
Explanation:

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

(4x + 8) = 5 (x + 8)
2

8x + 16 = 5x + 40

3x = 24

x = 8.

Hence, required ratio = (4x + 16) = 48 = 2.
(x + 16) 24

Discussion:
319 comments Page 9 of 32.

Parul said:   1 decade ago
How (x+8) ?

M.karthik said:   1 decade ago
How (4x+16) / (x+16) is = 48/24.

Please explain.

Ashu said:   1 decade ago
Although, I got the solution but cann't we add 16 in the second step, as the fater age is increased by 16 I. E 8 and further 8 years.

Uttam said:   1 decade ago
Age of son=x
then,
(x+3x)=4x
after 8 years
(4x+8)=2.5(x+8)
8x+16=5x+40
x=8
after 8 years
(4x+16)=y(x+16)
wkt x=8
s0,
y=(32+16)/(8+16)
y=2.

DINESH REDDY said:   1 decade ago
Ya 4x is absolutely right.

Rudra said:   1 decade ago
Thanx vaishu for your answer of the last step

Vinod said:   1 decade ago
Thank you vaishu.

Dimple said:   1 decade ago
Acc to me 5/2 multiplied on fathers side?

Pari said:   1 decade ago
Can anyone clear how d equation of(4x+16)/(x+16) is = 48/24

I mean from where these values 48/24 are coming...
plz clarify this point only

Pari said:   1 decade ago
Ohhh got it ...we are to put d value of x i.e 8 in d equation...:)

= (4x+16)/(x+16)
= (4x8+16)/(8x16)
= 48/24
= 2 times
:)


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