Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
2 times
1 times
2
3 times
4
3 times
Answer: Option
Explanation:

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

(4x + 8) = 5 (x + 8)
2

8x + 16 = 5x + 40

3x = 24

x = 8.

Hence, required ratio = (4x + 16) = 48 = 2.
(x + 16) 24

Discussion:
319 comments Page 8 of 32.

Affrin said:   1 decade ago
(4x+8)=5/2(x+8) => 8x+16 = 5x+40

bcoz :
cross multiply : 2(4x+8) = 8x+16
straight multiply: 5(x+8) = 5x+40
Everyone clear.........

Affrin said:   1 decade ago
THANKS. Vaishu for your explanation.

Sajitha said:   1 decade ago
Thank you very much affrin.

Vivek said:   1 decade ago
2 1/2 means (2*2+1)/2 so dats 5/2

Abhiruchi said:   1 decade ago
How (4x+16) / (x+16) is = 48/24 ?

Please explain.

Gauri said:   1 decade ago
thanks vaishu, for solving the problem for the last ratio

Manu said:   1 decade ago
I want details answer for 4x+16/x+16 and how did we get answer 48/24 please. Reply me.

Nagarjun said:   1 decade ago
Thank you vaishu. I am satisfied after reading your answer.

Nayana said:   1 decade ago
Hi vaishu,

I didn't get the last step why did you add 8 to that equation 4x+8 and x+8. Can you please explain me that last step?

Mahananda said:   1 decade ago
Hi vaishu,

I didn't get the step of adding 8 to 4x+8 &x+8. so pls explain me


Post your comments here:

Your comments will be displayed after verification.