Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
319 comments Page 8 of 32.
Mantsss said:
1 decade ago
@Ibbu.
As said in the problem itself.,
father is two and a half years older than his son after 8 years.
So.,
2*(1/2)=((2*2)+1)/2=5/2.
Or you can think as - five divided by 2 always equals to, two and a half...!!!
Got it...??? :).
As said in the problem itself.,
father is two and a half years older than his son after 8 years.
So.,
2*(1/2)=((2*2)+1)/2=5/2.
Or you can think as - five divided by 2 always equals to, two and a half...!!!
Got it...??? :).
Chithra said:
1 decade ago
We have 4x+8 = x+8.
Further 8 years means we need to add another 8 on both side,
i.e.. 4x+8+8=x+8+8, which becomes 4x+16=x+16.
We can also write this as (4x+16)/(x+16). Then substitute the value of 8 in that we will get the answer.
Further 8 years means we need to add another 8 on both side,
i.e.. 4x+8+8=x+8+8, which becomes 4x+16=x+16.
We can also write this as (4x+16)/(x+16). Then substitute the value of 8 in that we will get the answer.
Dhaval said:
2 years ago
Father (F) = 3S (son).
After 8 year;
F + 8 = 5/2(S + 8)
Put F = 3S.
After Solution S = 24.
Now in the present time so before 8 year;
S =24 - 8 = 16.
Now F = 3S.
F = 3×16 = 48.
After further 8 years.
So, Father/son = 48/24.
Ans. 2.
After 8 year;
F + 8 = 5/2(S + 8)
Put F = 3S.
After Solution S = 24.
Now in the present time so before 8 year;
S =24 - 8 = 16.
Now F = 3S.
F = 3×16 = 48.
After further 8 years.
So, Father/son = 48/24.
Ans. 2.
(12)
Suraj said:
7 years ago
@Sanju.
They've stated that Father's age is 3 times more than son's age.
Not 3 times of fathers age.
then;
If son's age is 'x' then according to the statement "3 TIMES MORE THAN SON'S AGE" Means 3x+x.
Thus, 3x+x=4x.
They've stated that Father's age is 3 times more than son's age.
Not 3 times of fathers age.
then;
If son's age is 'x' then according to the statement "3 TIMES MORE THAN SON'S AGE" Means 3x+x.
Thus, 3x+x=4x.
Gora4663 said:
4 years ago
Let son age = x
Father age = y.
X + 3x =y( acc to 1st statemnt) ---> eq1
5/2(X+8) = y+8
5x+40 = 2y+16
5x-2y=-24 ---> eq2.
Solve eq 1 and 2 we get;
X=8 then y = 24,
After 16 year,
Son age 24 & father age 48.
Therefore 2 times.
Father age = y.
X + 3x =y( acc to 1st statemnt) ---> eq1
5/2(X+8) = y+8
5x+40 = 2y+16
5x-2y=-24 ---> eq2.
Solve eq 1 and 2 we get;
X=8 then y = 24,
After 16 year,
Son age 24 & father age 48.
Therefore 2 times.
Manohar said:
1 decade ago
Try this way now the ratio is
4: 1
8 (4x2)=8 8-5=3x=8(5-2)
5 :2 5x1)=5 x=8
32 8 after 8 yrs 40 16 further 8 yrs 48 24 2;1
4: 1
8 (4x2)=8 8-5=3x=8(5-2)
5 :2 5x1)=5 x=8
32 8 after 8 yrs 40 16 further 8 yrs 48 24 2;1
Hamza said:
3 years ago
@All.
Please explain, father is two and a half mean 5/2. Then why we write 5/2 With son's age?
Because when any question ask father is 5 times of son then we put father is 5x and son is x.
Anyone, please explain this.
Please explain, father is two and a half mean 5/2. Then why we write 5/2 With son's age?
Because when any question ask father is 5 times of son then we put father is 5x and son is x.
Anyone, please explain this.
Rahul said:
9 years ago
Anil got married 8 years ago. His present age is 6/5 times his age at the time of his marriage. Anil's sister was 10 years younger to him at the time of his marriage. The age of Anils sister is?
Solve this problem.
Solve this problem.
(1)
Madhav said:
4 years ago
Let fathers age be f and son age be s
given
f= 3s+s = 4s.
f + 8 = 2 * (s+8) = 5/2 (s+8).
So 4s +8 =5/2 (s+8)we get s=8, also f= 4*8 =32.
Let x times.
Given,
(f+16) = x(s+16)substitute f and s value,
we get x=2.
given
f= 3s+s = 4s.
f + 8 = 2 * (s+8) = 5/2 (s+8).
So 4s +8 =5/2 (s+8)we get s=8, also f= 4*8 =32.
Let x times.
Given,
(f+16) = x(s+16)substitute f and s value,
we get x=2.
Villasnjsjs said:
2 years ago
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
2(4x + 8) = 5(x + 8).
8x + 16 = 5x + 40.
3x = 24.
x = 8.
Hence, required ratio = (4x + 16) = 48 = 2.
Then (x + 16)24.
2(4x + 8) = 5(x + 8).
8x + 16 = 5x + 40.
3x = 24.
x = 8.
Hence, required ratio = (4x + 16) = 48 = 2.
Then (x + 16)24.
(11)
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