Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
326 comments Page 8 of 33.
Amey said:
3 years ago
@All.
Here, If x = 8 then 3 times more is 24 which is the father's age and after 8 more years x = 16 and the father's age will be 32 which is not 2 and a half times 16..
So, 3x is correct and x + 3x is wrong.
So, the correct answer will be 2.5.
Here, If x = 8 then 3 times more is 24 which is the father's age and after 8 more years x = 16 and the father's age will be 32 which is not 2 and a half times 16..
So, 3x is correct and x + 3x is wrong.
So, the correct answer will be 2.5.
(15)
Arjun said:
1 decade ago
@Cosmicguypradeep
Let the age of the son be "x"
father is aged 3 times more than his son so x+3x=4x }(i agree this part)
after 8 years,
4x+8=x+8....equation (1)( doubt here q1: how X=4X that is how father age is equal to son age )
Let the age of the son be "x"
father is aged 3 times more than his son so x+3x=4x }(i agree this part)
after 8 years,
4x+8=x+8....equation (1)( doubt here q1: how X=4X that is how father age is equal to son age )
Abhishek Zatakiya said:
2 years ago
Let son age = x.
Father age = y.
X + 3x = y( acc to 1st statemnt) ---> eq1
5/2(X+8) = y+8.
5x+40 = 2y+16.
5x-2y=-24 ---> eq2.
Solve eq 1 and 2 we get;
X=8 then y = 24,
After 16 years,
Son age 24 & father age 48.
Therefore 2 times.
Father age = y.
X + 3x = y( acc to 1st statemnt) ---> eq1
5/2(X+8) = y+8.
5x+40 = 2y+16.
5x-2y=-24 ---> eq2.
Solve eq 1 and 2 we get;
X=8 then y = 24,
After 16 years,
Son age 24 & father age 48.
Therefore 2 times.
(31)
Mantsss said:
1 decade ago
@Ibbu.
As said in the problem itself.,
father is two and a half years older than his son after 8 years.
So.,
2*(1/2)=((2*2)+1)/2=5/2.
Or you can think as - five divided by 2 always equals to, two and a half...!!!
Got it...??? :).
As said in the problem itself.,
father is two and a half years older than his son after 8 years.
So.,
2*(1/2)=((2*2)+1)/2=5/2.
Or you can think as - five divided by 2 always equals to, two and a half...!!!
Got it...??? :).
Chithra said:
1 decade ago
We have 4x+8 = x+8.
Further 8 years means we need to add another 8 on both side,
i.e.. 4x+8+8=x+8+8, which becomes 4x+16=x+16.
We can also write this as (4x+16)/(x+16). Then substitute the value of 8 in that we will get the answer.
Further 8 years means we need to add another 8 on both side,
i.e.. 4x+8+8=x+8+8, which becomes 4x+16=x+16.
We can also write this as (4x+16)/(x+16). Then substitute the value of 8 in that we will get the answer.
Dhaval said:
3 years ago
Father (F) = 3S (son).
After 8 year;
F + 8 = 5/2(S + 8)
Put F = 3S.
After Solution S = 24.
Now in the present time so before 8 year;
S =24 - 8 = 16.
Now F = 3S.
F = 3×16 = 48.
After further 8 years.
So, Father/son = 48/24.
Ans. 2.
After 8 year;
F + 8 = 5/2(S + 8)
Put F = 3S.
After Solution S = 24.
Now in the present time so before 8 year;
S =24 - 8 = 16.
Now F = 3S.
F = 3×16 = 48.
After further 8 years.
So, Father/son = 48/24.
Ans. 2.
(12)
Suraj said:
8 years ago
@Sanju.
They've stated that Father's age is 3 times more than son's age.
Not 3 times of fathers age.
then;
If son's age is 'x' then according to the statement "3 TIMES MORE THAN SON'S AGE" Means 3x+x.
Thus, 3x+x=4x.
They've stated that Father's age is 3 times more than son's age.
Not 3 times of fathers age.
then;
If son's age is 'x' then according to the statement "3 TIMES MORE THAN SON'S AGE" Means 3x+x.
Thus, 3x+x=4x.
Gora4663 said:
5 years ago
Let son age = x
Father age = y.
X + 3x =y( acc to 1st statemnt) ---> eq1
5/2(X+8) = y+8
5x+40 = 2y+16
5x-2y=-24 ---> eq2.
Solve eq 1 and 2 we get;
X=8 then y = 24,
After 16 year,
Son age 24 & father age 48.
Therefore 2 times.
Father age = y.
X + 3x =y( acc to 1st statemnt) ---> eq1
5/2(X+8) = y+8
5x+40 = 2y+16
5x-2y=-24 ---> eq2.
Solve eq 1 and 2 we get;
X=8 then y = 24,
After 16 year,
Son age 24 & father age 48.
Therefore 2 times.
Manohar said:
1 decade ago
Try this way now the ratio is
4: 1
8 (4x2)=8 8-5=3x=8(5-2)
5 :2 5x1)=5 x=8
32 8 after 8 yrs 40 16 further 8 yrs 48 24 2;1
4: 1
8 (4x2)=8 8-5=3x=8(5-2)
5 :2 5x1)=5 x=8
32 8 after 8 yrs 40 16 further 8 yrs 48 24 2;1
Hamza said:
4 years ago
@All.
Please explain, father is two and a half mean 5/2. Then why we write 5/2 With son's age?
Because when any question ask father is 5 times of son then we put father is 5x and son is x.
Anyone, please explain this.
Please explain, father is two and a half mean 5/2. Then why we write 5/2 With son's age?
Because when any question ask father is 5 times of son then we put father is 5x and son is x.
Anyone, please explain this.
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