Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
319 comments Page 9 of 32.
Pankaj said:
1 decade ago
As the in statement state that fathers age would be 2 and 1/2 of the ronits ages.
Ronits age is x,
his fathers age is x+3x=4x,
after 8 yaers
(4x+8) = 2*1/2(x+8)
multiply 2*1/2 i.e (2*2+1)/2=5/2
4x+8 =5/2(x+8)
Ronits age is x,
his fathers age is x+3x=4x,
after 8 yaers
(4x+8) = 2*1/2(x+8)
multiply 2*1/2 i.e (2*2+1)/2=5/2
4x+8 =5/2(x+8)
Prameela said:
8 months ago
Here is how 5:2 comes;
Initially it was 2.5:1.
To remove the decimal point,we need to multiply by 10 in the numerator and denominator also.
= 2.5/1 x10/10.
= 25/10 (on cancellation with 5, it becomes),
= 5:2.
Initially it was 2.5:1.
To remove the decimal point,we need to multiply by 10 in the numerator and denominator also.
= 2.5/1 x10/10.
= 25/10 (on cancellation with 5, it becomes),
= 5:2.
(7)
NOOR said:
1 decade ago
Three times parents age of a father is equal to eight time age of his son. Eight years hence the father will twice as old as his son at that time. What are the parent ages?
Can any body solve this question?
Can any body solve this question?
Nebin said:
1 decade ago
Present age s=24, f=72(3 times more than).
After 8 years s=32, f=80(now two and half times).
Again after 8 years s=40, f=88(now 2.2 times). I got like this please give correct answer..is it correct or not?
After 8 years s=32, f=80(now two and half times).
Again after 8 years s=40, f=88(now 2.2 times). I got like this please give correct answer..is it correct or not?
Supriya said:
1 decade ago
It is given in the question that Father is aged three times more than his son Ronit and v have taken Ronit's age as x and father's age as 3x.
Since father age is MORE THAN his son's age it is x+3x.
Since father age is MORE THAN his son's age it is x+3x.
Lillyane67 said:
1 decade ago
And as @newbie said, if its correct then I am failing to understand that why is 3x + 8 = 2.5 x ? Shouldn't it be 3x + 8 = 2.5 (x + 8), because even the son's age should have been added to 8 right ?
Srikath said:
10 years ago
First time more than 3 years of his son's age, after 8 years 2 and 1/2 years of Ronit age. Then finally 2 times of his son's age.
If you observe 1/2 times decreasing in ratio so its only guess.
If you observe 1/2 times decreasing in ratio so its only guess.
Janu said:
1 decade ago
After Means We have to add plus symbol. So after 8 years means 4x+8 then another after 8 years means add another plus 8 so it become 4x+8+8. So equation become 4x+16. Like that For Rohit x+16.
Payal said:
7 years ago
Ronit age = X.
Father age = 3x.
After 8 years.
(X+8) = (3x+8).
Half of of Ronit age.
(X+8) =1/2(3x+8).
X=8.
After further 8 years.
Both age ratio, where X = 8.
(3x+8)/X+8 = 32/16.
=> 2.
Father age = 3x.
After 8 years.
(X+8) = (3x+8).
Half of of Ronit age.
(X+8) =1/2(3x+8).
X=8.
After further 8 years.
Both age ratio, where X = 8.
(3x+8)/X+8 = 32/16.
=> 2.
(1)
Santhiya said:
7 years ago
@All.
Simply, the solution is;
Given:
Ist father age= 3 times more than son age.
2nd after 8yrs father age= 2 1/2 times more than son age.
3rd after 8 yrs age =2 time more than son age.
Simply, the solution is;
Given:
Ist father age= 3 times more than son age.
2nd after 8yrs father age= 2 1/2 times more than son age.
3rd after 8 yrs age =2 time more than son age.
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