Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
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(4x + 8) = | 5 | (x + 8) |
2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
(x + 16) | 24 |
Discussion:
319 comments Page 6 of 32.
Manisha Prasad said:
1 decade ago
Father is aged three times more than his son Ronit = four times of son's age. Is it justified?
Three times more = four times.
HOW can we say this?
Three times more means it could be 3x+1, or 3x+2,.....or five times....it could be anything..
So how can we say three times more = four times.
Three times more = four times.
HOW can we say this?
Three times more means it could be 3x+1, or 3x+2,.....or five times....it could be anything..
So how can we say three times more = four times.
Er. Pradeep Maurya said:
1 decade ago
Hi @Seema.
Here BODMAS rules are applied, where we solved first brackets (4x+16).
Put x = 4 then (4*8+16) = 48.
Then next brackets (x+16). Put again x = 8 then (8+16) = 24.
Now please see the sign between both the brackets that is divide sign, so please now divide 48/28 = 2.
Thank You.
Here BODMAS rules are applied, where we solved first brackets (4x+16).
Put x = 4 then (4*8+16) = 48.
Then next brackets (x+16). Put again x = 8 then (8+16) = 24.
Now please see the sign between both the brackets that is divide sign, so please now divide 48/28 = 2.
Thank You.
Shweta chaubey said:
1 decade ago
Son present age is =x
than father's present age is=more than 3 times of son age
=x+3x
According to the question,
after 8 years..
x+8=x+3x+8
x+8=4x+8
and father will be 5/2 greater than son
5/2(x+8)=4x+8
5x+40=8x+16
3x=24
x=8
ratio after 8 years
4x+8+8/x+8+8=6/3=2
than father's present age is=more than 3 times of son age
=x+3x
According to the question,
after 8 years..
x+8=x+3x+8
x+8=4x+8
and father will be 5/2 greater than son
5/2(x+8)=4x+8
5x+40=8x+16
3x=24
x=8
ratio after 8 years
4x+8+8/x+8+8=6/3=2
Amrutha said:
1 decade ago
Rohit age is x and his father age is 3x ofter 8 years rohit age is 5/2(x+8) and his father age is 3x+8 therefore
3x+8=5/2(x+8)
6x+16=5x+40
x=24
Rohit age is 24 then his father age is 72 year ofter 8 years
It becomes 32 and 80 it is exactly 2 1/2 times of rohit age so answer is 2 times.
3x+8=5/2(x+8)
6x+16=5x+40
x=24
Rohit age is 24 then his father age is 72 year ofter 8 years
It becomes 32 and 80 it is exactly 2 1/2 times of rohit age so answer is 2 times.
Samanth kumar said:
6 years ago
How the ratio is 3:1?
It is 4:1 since in question it is clearly mentioned that "3 TIMES MORE THAN RONIT ".
Then only you'll get answer, never forget this if in question it says 3 times than another ratio will be 3:1, if it says 3 times more than or larger than other you should take 4:1.
It is 4:1 since in question it is clearly mentioned that "3 TIMES MORE THAN RONIT ".
Then only you'll get answer, never forget this if in question it says 3 times than another ratio will be 3:1, if it says 3 times more than or larger than other you should take 4:1.
Selva said:
9 years ago
if Father is aged three times more than his son Ronit means, 3x + x = 4x then After 8 years, he would be two and a half times of Ronit's age.
In that above 'he' represent Ronit's father which means
(3x + 8) = 5/2(x + 8) right?
Then, how it will be (4x + 8) = 5/2(x + 8)?
In that above 'he' represent Ronit's father which means
(3x + 8) = 5/2(x + 8) right?
Then, how it will be (4x + 8) = 5/2(x + 8)?
Karuna said:
1 decade ago
(4x+8)=5/2(x+8) please can u explain me how this step came...
means,
father age was 4x sun age was x
next after 8 years,
father age was 4x+8 sun age was x+8
Now he would be 2 and half times more than his son right then,
Here i didn't get...
means,
father age was 4x sun age was x
next after 8 years,
father age was 4x+8 sun age was x+8
Now he would be 2 and half times more than his son right then,
Here i didn't get...
Saresh said:
1 decade ago
All are wrong answer.
Current answer is 2 1/5 time.
That is father first age is 72 answer his son age is 24 (3:1).
After 8 years father age is 80 and son age is 32 (1: 2. 5).
After 8 years father age is 88 and son age will be 40 (1: 1. 2).
So all option are incorrect.
Current answer is 2 1/5 time.
That is father first age is 72 answer his son age is 24 (3:1).
After 8 years father age is 80 and son age is 32 (1: 2. 5).
After 8 years father age is 88 and son age will be 40 (1: 1. 2).
So all option are incorrect.
Varinder said:
9 years ago
@ Harsh
See Rohit present age comes out to be 8.
His father age is 32.
Now add 8 to both of these. Will be 16 and 40 respectively. Later is 2.5 times the former, adding 8, they will be 24 and 48 with latter is 2 times the former which is the answer. Hope it worked
See Rohit present age comes out to be 8.
His father age is 32.
Now add 8 to both of these. Will be 16 and 40 respectively. Later is 2.5 times the former, adding 8, they will be 24 and 48 with latter is 2 times the former which is the answer. Hope it worked
Vaibhav said:
1 year ago
@All.
This question is a tricky one, as it states Father's age is three times more than Ronit's age. The "times" would imply F=3R but it also has a "more" statement. Meaning that Father's age is what adds to 3 times Ronit's age to Ronit's age, which means.
F = 3R+R.
This question is a tricky one, as it states Father's age is three times more than Ronit's age. The "times" would imply F=3R but it also has a "more" statement. Meaning that Father's age is what adds to 3 times Ronit's age to Ronit's age, which means.
F = 3R+R.
(48)
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