Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
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(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
326 comments Page 5 of 33.
Hrishikesh Shelar said:
9 years ago
Father is Tree times more than his son.
i.e. Ronit age is also considered while calculating his father age so, Ronit age+ 3*Ronit age = His father's age. Here " Father more than" this word is important.
If Suppose Question is as Father's age is three time the Ronit age then & then only it 3X.
2. Two & half means 2+1/2= 5/2.
Good luck!
i.e. Ronit age is also considered while calculating his father age so, Ronit age+ 3*Ronit age = His father's age. Here " Father more than" this word is important.
If Suppose Question is as Father's age is three time the Ronit age then & then only it 3X.
2. Two & half means 2+1/2= 5/2.
Good luck!
Rakesh said:
11 months ago
@All.
Simply;
Ronith's present age = x.
Father's age=3 times more than Ronith's age.
So, x + 3x = 4x.
So, after 8 years, 4x + 8 = 5/2(x+8) by doing the calculation we will x = 8.
Further 8 years:
Now we are in the present stage, so they have asked for a further 8 years,
So, a further 8 years and an additional 8 years =16 years.
=> 4x + 16/x + 16+2.
Simply;
Ronith's present age = x.
Father's age=3 times more than Ronith's age.
So, x + 3x = 4x.
So, after 8 years, 4x + 8 = 5/2(x+8) by doing the calculation we will x = 8.
Further 8 years:
Now we are in the present stage, so they have asked for a further 8 years,
So, a further 8 years and an additional 8 years =16 years.
=> 4x + 16/x + 16+2.
(12)
Neha said:
7 years ago
Son- x father- 3x BUT, it is said MORE than 3 times so x +3x= 4x.
Now, 8 years ahead, son= x+8 and father= 5/2*(x+8).
---> (x+8)=5/2*(x+8),
---> 2(x+8)=5(x+8),
---> 2x + 16= 5x + 40,
---> x= 8 - sons age.
father is 4x= 4*8= 32.
NOW, in total 16 years is asked from the beginning,
So, sons age= 8+16= 24,
Fathers age= 32+16= 48,
48 is 2 times of 24!.
Now, 8 years ahead, son= x+8 and father= 5/2*(x+8).
---> (x+8)=5/2*(x+8),
---> 2(x+8)=5(x+8),
---> 2x + 16= 5x + 40,
---> x= 8 - sons age.
father is 4x= 4*8= 32.
NOW, in total 16 years is asked from the beginning,
So, sons age= 8+16= 24,
Fathers age= 32+16= 48,
48 is 2 times of 24!.
Ravee said:
1 decade ago
Hi Sharaddha here sum explansn to your doubt.
As you said Father's age is three times then son's age.
Here x or 1x both are same, I think you done this way.
"X", to this three times as 1x, 2x, 3x.
This way u'll get 3x, but we know X and 1X are same so.
To X (or 1X both are same) it is three times as 2x, 3x, 4x.
Now the F's age is X+3X=4X.
As you said Father's age is three times then son's age.
Here x or 1x both are same, I think you done this way.
"X", to this three times as 1x, 2x, 3x.
This way u'll get 3x, but we know X and 1X are same so.
To X (or 1X both are same) it is three times as 2x, 3x, 4x.
Now the F's age is X+3X=4X.
Yella Subba Pragada Rao said:
3 weeks ago
4X+8 = (X+8) * 2.5,
4X+8 = 2.5X + 20,
1.5X = 12,
X = 8
If X=8, Then Father age is 32 (Four times X)
Now, After Eight years Ronith age is 16, Father age is 40 which is 2.5 times of Ronith age.
Later, After further Eight years Ronith age is 24, Father age is 48.
That means Father age is Two times of Ronith age.
So Answer is Option A) 2 times.
4X+8 = 2.5X + 20,
1.5X = 12,
X = 8
If X=8, Then Father age is 32 (Four times X)
Now, After Eight years Ronith age is 16, Father age is 40 which is 2.5 times of Ronith age.
Later, After further Eight years Ronith age is 24, Father age is 48.
That means Father age is Two times of Ronith age.
So Answer is Option A) 2 times.
COOLCALM said:
9 years ago
Father F and Rohit R.
So, F = 3R + R = 4R.
After 8 years,
F + 8 = 2 1/2 (R + 8) means, F + 8 = 5/2 (R + 8).
So, 2(F + 8) = 5R + 40,
2(4R + 8) = 5R + 40,
8R + 16 = 5R + 40,
3R = 24,
R = 8.
Rohit's present age = 8 years.
After 16 years of present day (8 + 8).
Ratio would be F + 16/ R + 16.
So, 4R + 16/R + 16,
4(8) + 16/8 + 16 = 48/24 = 2.
So, F = 3R + R = 4R.
After 8 years,
F + 8 = 2 1/2 (R + 8) means, F + 8 = 5/2 (R + 8).
So, 2(F + 8) = 5R + 40,
2(4R + 8) = 5R + 40,
8R + 16 = 5R + 40,
3R = 24,
R = 8.
Rohit's present age = 8 years.
After 16 years of present day (8 + 8).
Ratio would be F + 16/ R + 16.
So, 4R + 16/R + 16,
4(8) + 16/8 + 16 = 48/24 = 2.
Honey said:
1 year ago
Ronith's present age = x.
Father's age=3 times more of Ronith's age.
So, x + 3x = 4x.
So, after 8 years, 4x + 8 = 5/2(x+8) by doing the calculation we will x = 8.
Further 8 years: Now we are in the present stage, so they have asked for a further 8 years, so future 8 years and a further 8 years =16 years.
=> 4x + 16/x + 16+2.
Father's age=3 times more of Ronith's age.
So, x + 3x = 4x.
So, after 8 years, 4x + 8 = 5/2(x+8) by doing the calculation we will x = 8.
Further 8 years: Now we are in the present stage, so they have asked for a further 8 years, so future 8 years and a further 8 years =16 years.
=> 4x + 16/x + 16+2.
(11)
Janarthanan said:
1 year ago
@All.
My doubt is; in the question, it is given "Father has aged 3times the son" then how father's age will be x + 3x = 4x? If 4x is father age then it will become wrong. right?
Ex. Let son age be 2 years, father age will be 8years (4x, as given in explanation). Then how it will be correct?
Anyone, explain this to me.
My doubt is; in the question, it is given "Father has aged 3times the son" then how father's age will be x + 3x = 4x? If 4x is father age then it will become wrong. right?
Ex. Let son age be 2 years, father age will be 8years (4x, as given in explanation). Then how it will be correct?
Anyone, explain this to me.
(62)
Naveen I S said:
1 decade ago
Let us assume Ronit age is 10 years, Father age is 3 times of Ronit age, so 10*3 = 30 years.
After 8 years Ronit age will 18 years father age will be 2.5 times of son age, so 2.5*18 = 45 years.
After 8 years father age would be 45 + 8 = 53 years and Ronit age would be 26 years.
So, 53/26 = 2.03.
Answer is 2 times.
After 8 years Ronit age will 18 years father age will be 2.5 times of son age, so 2.5*18 = 45 years.
After 8 years father age would be 45 + 8 = 53 years and Ronit age would be 26 years.
So, 53/26 = 2.03.
Answer is 2 times.
Harsh Vardhan said:
10 years ago
Father's age is 3x + x = 4x.
After putting 4x in the equation of 4x + 8 = 5/2(x + 8), then I got 8.
Further, I found that son's age is 8 and father's age is 32 because F = 4x.
Later I made an equation F's age + 8 = Son's age + 8 * y (i.e. F + 8 = 8 + 8 * y). I can't find the solution.
Please help me out.
After putting 4x in the equation of 4x + 8 = 5/2(x + 8), then I got 8.
Further, I found that son's age is 8 and father's age is 32 because F = 4x.
Later I made an equation F's age + 8 = Son's age + 8 * y (i.e. F + 8 = 8 + 8 * y). I can't find the solution.
Please help me out.
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