Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
319 comments Page 5 of 32.
Rakesh said:
3 months ago
@All.
Simply;
Ronith's present age = x.
Father's age=3 times more than Ronith's age.
So, x + 3x = 4x.
So, after 8 years, 4x + 8 = 5/2(x+8) by doing the calculation we will x = 8.
Further 8 years:
Now we are in the present stage, so they have asked for a further 8 years,
So, a further 8 years and an additional 8 years =16 years.
=> 4x + 16/x + 16+2.
Simply;
Ronith's present age = x.
Father's age=3 times more than Ronith's age.
So, x + 3x = 4x.
So, after 8 years, 4x + 8 = 5/2(x+8) by doing the calculation we will x = 8.
Further 8 years:
Now we are in the present stage, so they have asked for a further 8 years,
So, a further 8 years and an additional 8 years =16 years.
=> 4x + 16/x + 16+2.
(10)
Neha said:
7 years ago
Son- x father- 3x BUT, it is said MORE than 3 times so x +3x= 4x.
Now, 8 years ahead, son= x+8 and father= 5/2*(x+8).
---> (x+8)=5/2*(x+8),
---> 2(x+8)=5(x+8),
---> 2x + 16= 5x + 40,
---> x= 8 - sons age.
father is 4x= 4*8= 32.
NOW, in total 16 years is asked from the beginning,
So, sons age= 8+16= 24,
Fathers age= 32+16= 48,
48 is 2 times of 24!.
Now, 8 years ahead, son= x+8 and father= 5/2*(x+8).
---> (x+8)=5/2*(x+8),
---> 2(x+8)=5(x+8),
---> 2x + 16= 5x + 40,
---> x= 8 - sons age.
father is 4x= 4*8= 32.
NOW, in total 16 years is asked from the beginning,
So, sons age= 8+16= 24,
Fathers age= 32+16= 48,
48 is 2 times of 24!.
Ravee said:
1 decade ago
Hi Sharaddha here sum explansn to your doubt.
As you said Father's age is three times then son's age.
Here x or 1x both are same, I think you done this way.
"X", to this three times as 1x, 2x, 3x.
This way u'll get 3x, but we know X and 1X are same so.
To X (or 1X both are same) it is three times as 2x, 3x, 4x.
Now the F's age is X+3X=4X.
As you said Father's age is three times then son's age.
Here x or 1x both are same, I think you done this way.
"X", to this three times as 1x, 2x, 3x.
This way u'll get 3x, but we know X and 1X are same so.
To X (or 1X both are same) it is three times as 2x, 3x, 4x.
Now the F's age is X+3X=4X.
COOLCALM said:
9 years ago
Father F and Rohit R.
So, F = 3R + R = 4R.
After 8 years,
F + 8 = 2 1/2 (R + 8) means, F + 8 = 5/2 (R + 8).
So, 2(F + 8) = 5R + 40,
2(4R + 8) = 5R + 40,
8R + 16 = 5R + 40,
3R = 24,
R = 8.
Rohit's present age = 8 years.
After 16 years of present day (8 + 8).
Ratio would be F + 16/ R + 16.
So, 4R + 16/R + 16,
4(8) + 16/8 + 16 = 48/24 = 2.
So, F = 3R + R = 4R.
After 8 years,
F + 8 = 2 1/2 (R + 8) means, F + 8 = 5/2 (R + 8).
So, 2(F + 8) = 5R + 40,
2(4R + 8) = 5R + 40,
8R + 16 = 5R + 40,
3R = 24,
R = 8.
Rohit's present age = 8 years.
After 16 years of present day (8 + 8).
Ratio would be F + 16/ R + 16.
So, 4R + 16/R + 16,
4(8) + 16/8 + 16 = 48/24 = 2.
Honey said:
7 months ago
Ronith's present age = x.
Father's age=3 times more of Ronith's age.
So, x + 3x = 4x.
So, after 8 years, 4x + 8 = 5/2(x+8) by doing the calculation we will x = 8.
Further 8 years: Now we are in the present stage, so they have asked for a further 8 years, so future 8 years and a further 8 years =16 years.
=> 4x + 16/x + 16+2.
Father's age=3 times more of Ronith's age.
So, x + 3x = 4x.
So, after 8 years, 4x + 8 = 5/2(x+8) by doing the calculation we will x = 8.
Further 8 years: Now we are in the present stage, so they have asked for a further 8 years, so future 8 years and a further 8 years =16 years.
=> 4x + 16/x + 16+2.
(10)
Janarthanan said:
5 months ago
@All.
My doubt is; in the question, it is given "Father has aged 3times the son" then how father's age will be x + 3x = 4x? If 4x is father age then it will become wrong. right?
Ex. Let son age be 2 years, father age will be 8years (4x, as given in explanation). Then how it will be correct?
Anyone, explain this to me.
My doubt is; in the question, it is given "Father has aged 3times the son" then how father's age will be x + 3x = 4x? If 4x is father age then it will become wrong. right?
Ex. Let son age be 2 years, father age will be 8years (4x, as given in explanation). Then how it will be correct?
Anyone, explain this to me.
(31)
Naveen I S said:
9 years ago
Let us assume Ronit age is 10 years, Father age is 3 times of Ronit age, so 10*3 = 30 years.
After 8 years Ronit age will 18 years father age will be 2.5 times of son age, so 2.5*18 = 45 years.
After 8 years father age would be 45 + 8 = 53 years and Ronit age would be 26 years.
So, 53/26 = 2.03.
Answer is 2 times.
After 8 years Ronit age will 18 years father age will be 2.5 times of son age, so 2.5*18 = 45 years.
After 8 years father age would be 45 + 8 = 53 years and Ronit age would be 26 years.
So, 53/26 = 2.03.
Answer is 2 times.
Harsh Vardhan said:
9 years ago
Father's age is 3x + x = 4x.
After putting 4x in the equation of 4x + 8 = 5/2(x + 8), then I got 8.
Further, I found that son's age is 8 and father's age is 32 because F = 4x.
Later I made an equation F's age + 8 = Son's age + 8 * y (i.e. F + 8 = 8 + 8 * y). I can't find the solution.
Please help me out.
After putting 4x in the equation of 4x + 8 = 5/2(x + 8), then I got 8.
Further, I found that son's age is 8 and father's age is 32 because F = 4x.
Later I made an equation F's age + 8 = Son's age + 8 * y (i.e. F + 8 = 8 + 8 * y). I can't find the solution.
Please help me out.
Neha said:
5 years ago
Let's Ronit present age be x.
Father's present age =3x.
After 8 yrs,
Ronits age = x+8.
Fathers age =3x+8.
3x+8=2.5(x+8)
X=24yrs.
Fathers age = 3x =3*24=72yrs
After a further 8 yrs,
Fathers age =72+8=80yrs,
Ronit's age=24+8=32yrs.
No.of times father age to Ronit age =80/32.
Then we get 2.5times(ans).
Father's present age =3x.
After 8 yrs,
Ronits age = x+8.
Fathers age =3x+8.
3x+8=2.5(x+8)
X=24yrs.
Fathers age = 3x =3*24=72yrs
After a further 8 yrs,
Fathers age =72+8=80yrs,
Ronit's age=24+8=32yrs.
No.of times father age to Ronit age =80/32.
Then we get 2.5times(ans).
Sree said:
4 years ago
Let Rohit age=X.
By condition:Fathers age=X + 3X,
After 8 yrs,
Fathers age=5/2(X+8).
So, 4x+8=5/2(x+8).
8x+16=5x+40.
X=8.
Sub x=8 in 5/2(x+8).
Ans:40.
After 8 yrs,
40+8=48.
Sons age present=8,
After 16 yrs, age=24,
24*2=48.
So, the answer is 3 times.
Thank you
By condition:Fathers age=X + 3X,
After 8 yrs,
Fathers age=5/2(X+8).
So, 4x+8=5/2(x+8).
8x+16=5x+40.
X=8.
Sub x=8 in 5/2(x+8).
Ans:40.
After 8 yrs,
40+8=48.
Sons age present=8,
After 16 yrs, age=24,
24*2=48.
So, the answer is 3 times.
Thank you
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