Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
319 comments Page 4 of 32.
Abhi said:
1 decade ago
Nothing to confuse .. Let take sons age as x. Then father age will become 4x as given in question (father's age is three times more than sons age read carefully its not fathers age is three times to sons age.. If three times to sons age means father age will become 3x).
After 8 yrs father age is 2 1/2 of sons age..So,
4x+8 = 2 1/2(x+8).
4x+8 = 5/2(x+8).
2(4x+8) = 5(x+8).
8x+16 = 5x+40.
3x = 24.
x = 8.
After 8 yrs father age is 2 1/2 of sons age..So,
4x+8 = 2 1/2(x+8).
4x+8 = 5/2(x+8).
2(4x+8) = 5(x+8).
8x+16 = 5x+40.
3x = 24.
x = 8.
Fuhar said:
1 decade ago
The last step is easy but division sign gone somewhere else. Fathers age is 4X + 8 + 8 (here 8 + 8 are the years later) now divide this with sons age which is x. But after 8 + 8 years it would be x + 8 + 8 as we got x value substitute in the both numerator and denominator there you go you get as 48/24 and we taking in ratio forms as options are given in ratio like two times the son age etc.
CHITHRA said:
1 decade ago
Hai Leenus, let us assume son's current age is x, fatther's age is 3 times more than that of son, so it will be x+3x=4x.
So present age of son is x and father is 4x. We want to find the ratio of ages after 16 years (8 and further 8, total 16).
So after 16 years fathers will be 4x+16 and son's will be x+16, hence that ratio came.
Now have alook at it, hope you will get that.
So present age of son is x and father is 4x. We want to find the ratio of ages after 16 years (8 and further 8, total 16).
So after 16 years fathers will be 4x+16 and son's will be x+16, hence that ratio came.
Now have alook at it, hope you will get that.
Cosmicguypradeep said:
1 decade ago
Simple
let the age of the son be "x"
father is aged 3 times more than his son so x+3x=4x
after 8 years,
4x+8=x+8....equation (1)
age will be 2 and half years i.e 2 1/2 = 5/2,
4x+8=5/2(x+8)
==> 8x+16=5x+40
==> x=8
after further 8 years;
4x+8+8=?(x+8+8)
4x+16=?(X+16)
==> ?=4x+16/x+16...equation (2)
==> substitute x=8 in eqution (2),
u will get ?=2
let the age of the son be "x"
father is aged 3 times more than his son so x+3x=4x
after 8 years,
4x+8=x+8....equation (1)
age will be 2 and half years i.e 2 1/2 = 5/2,
4x+8=5/2(x+8)
==> 8x+16=5x+40
==> x=8
after further 8 years;
4x+8+8=?(x+8+8)
4x+16=?(X+16)
==> ?=4x+16/x+16...equation (2)
==> substitute x=8 in eqution (2),
u will get ?=2
Sushil Verma said:
10 years ago
Guys it is very simple question I ll try to make you understand. Father is more than three times not three time so it will be 3x + x = 4x.
Then after 8 years father age will be 2.5 times than Ronit age= 5/2.
So 4x + 8/x + 8 = 5/2.
x=8.
Again after 8 years ratio will be 4x + 8 + 8/x + 8 + 8.
Let put the value of x so it will be = 4*8 + 8 + 8/8 + 8 + 8 = 48/24 = 2.
Then after 8 years father age will be 2.5 times than Ronit age= 5/2.
So 4x + 8/x + 8 = 5/2.
x=8.
Again after 8 years ratio will be 4x + 8 + 8/x + 8 + 8.
Let put the value of x so it will be = 4*8 + 8 + 8/8 + 8 + 8 = 48/24 = 2.
Ramesh said:
9 years ago
@Yalleswari.
As per the statement, x + 3x.
After 8 years, he would be 2 and a half times of his son.
So, x + 3x + 8 = x + 8.
4x + 8 = x + 8.
(4x + 8 ) = 5/2(x + 8).
We get, 8x + 16 = 5x + 40 => 3x = 24.
x = 8.
After further 8 years,
So add 8 to the equation 4x + 8 + 8 = x + 8+ 8.
4x + 16 = x + 16.
So the ratio is, (4x + 16)/(x + 16) = 48/24.
=> 2 years.
As per the statement, x + 3x.
After 8 years, he would be 2 and a half times of his son.
So, x + 3x + 8 = x + 8.
4x + 8 = x + 8.
(4x + 8 ) = 5/2(x + 8).
We get, 8x + 16 = 5x + 40 => 3x = 24.
x = 8.
After further 8 years,
So add 8 to the equation 4x + 8 + 8 = x + 8+ 8.
4x + 16 = x + 16.
So the ratio is, (4x + 16)/(x + 16) = 48/24.
=> 2 years.
Lokesh said:
2 years ago
As per the question, Father's age is 3 times more than the sons age.
Not 3 times of son's age..
That's why here is 3x+x.
Sons present age is = x
Father present age is = x+3x= 4x
After 8 years father's age would be -
4x+8 = 5/2(x+8).
By solving we get x=8,
now son's present age is x=8.
Father's age is 4x = 4*8= 32.
The required ratio 32+16/8+16 = 48/24 = 2 ans.
Not 3 times of son's age..
That's why here is 3x+x.
Sons present age is = x
Father present age is = x+3x= 4x
After 8 years father's age would be -
4x+8 = 5/2(x+8).
By solving we get x=8,
now son's present age is x=8.
Father's age is 4x = 4*8= 32.
The required ratio 32+16/8+16 = 48/24 = 2 ans.
(24)
Neethu said:
7 years ago
Let son age be x.
Father's age is 3 times more than son's age.
Which means x+3x=4x.
After 8years.
X+8=2 and half of x.
When we solve the equation we will get x as 8.
4x=32,
In the beginning of the question state that father's age is 3 times more than son age.
So x=8 then 3x=24.
After further 8years it becomes,
32+8=40.
3*8=24 and 5*8=40,
3-5=2.
and 2 times.
Father's age is 3 times more than son's age.
Which means x+3x=4x.
After 8years.
X+8=2 and half of x.
When we solve the equation we will get x as 8.
4x=32,
In the beginning of the question state that father's age is 3 times more than son age.
So x=8 then 3x=24.
After further 8years it becomes,
32+8=40.
3*8=24 and 5*8=40,
3-5=2.
and 2 times.
DINESH BAWA said:
6 years ago
Answer is 2.
ratio
F:S
3:1 After 8 yr.
5:2
(check differance |3-5|=2 & |1-2|=1 we know that ratio diff. must be same bcoz father age +8 with son age also +8 yr).
F:S
9:3 - - - >(x3)
10:4 - - - > (x2)
diff. =1 because of +8yr.
i.e 1=8.
The resent age father 3x8=24 + after 8 yr = 32.
The present age son 1x8=8 + after 8 yr = 16.
F/S=32/16= 2.
ratio
F:S
3:1 After 8 yr.
5:2
(check differance |3-5|=2 & |1-2|=1 we know that ratio diff. must be same bcoz father age +8 with son age also +8 yr).
F:S
9:3 - - - >(x3)
10:4 - - - > (x2)
diff. =1 because of +8yr.
i.e 1=8.
The resent age father 3x8=24 + after 8 yr = 32.
The present age son 1x8=8 + after 8 yr = 16.
F/S=32/16= 2.
(1)
Hrishikesh Shelar said:
9 years ago
Father is Tree times more than his son.
i.e. Ronit age is also considered while calculating his father age so, Ronit age+ 3*Ronit age = His father's age. Here " Father more than" this word is important.
If Suppose Question is as Father's age is three time the Ronit age then & then only it 3X.
2. Two & half means 2+1/2= 5/2.
Good luck!
i.e. Ronit age is also considered while calculating his father age so, Ronit age+ 3*Ronit age = His father's age. Here " Father more than" this word is important.
If Suppose Question is as Father's age is three time the Ronit age then & then only it 3X.
2. Two & half means 2+1/2= 5/2.
Good luck!
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