Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
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(4x + 8) = | 5 | (x + 8) |
2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
(x + 16) | 24 |
Discussion:
319 comments Page 3 of 32.
Sundar said:
2 decades ago
Hi Guys!
It is 4x not 3x. (As Krithika said).
If the given statement is "Father is aged three times of his son Ronit's age", then it will be 3x.
But, the given statement is "Father is aged three times more than his son Ronit". So, it should be 4x.
Some answers to your other doubts:
1. How 5/2 came? Ans: "Two and a half times" can be written as 2.5 or 5/2.
2. How 16 came? Ans: 8 Years + Further 8 Years = 16 years.
Have a nice day for all!
It is 4x not 3x. (As Krithika said).
If the given statement is "Father is aged three times of his son Ronit's age", then it will be 3x.
But, the given statement is "Father is aged three times more than his son Ronit". So, it should be 4x.
Some answers to your other doubts:
1. How 5/2 came? Ans: "Two and a half times" can be written as 2.5 or 5/2.
2. How 16 came? Ans: 8 Years + Further 8 Years = 16 years.
Have a nice day for all!
(4)
Ragav said:
7 years ago
Let the age of son be x then age of father will be 4x so we have ratio of father and son equals to 4x:x again after 8 years this becomes 5/2x:x as we all know that difference of age remains same then to make it same multiply above by 2 so that it becomes 5x:2x.
Therefore in 8 years 4x becomes 5x hence x is equal to 8 putting the value we get the age equal to 40 and 16 respectively and after 8 more years it will become 48 and 24 and hence father's age will be twice of the son.
Therefore in 8 years 4x becomes 5x hence x is equal to 8 putting the value we get the age equal to 40 and 16 respectively and after 8 more years it will become 48 and 24 and hence father's age will be twice of the son.
Shushant mishra said:
9 years ago
Let the age of son be x then age of father will be 4x so we have ratio of father and son equals to 4x:x again after 8 years this becomes 5/2x:x as we all know that difference of age remains same then to make it same multiply above by 2 so that it becomes 5x:2x, therefore in 8 years 4x becomes 5x hence x is equal to 8 putting the value we get the age equal to 40 and 16 respectively and after 8 more years it will become 48 and 24 and hence father's age will be twice of son.
Vignesh said:
9 years ago
You can also solve this problem by taking son's age as x and father's age as y. First, y = 4x as it is 3 times 'more' than that of his son. Then after 8 years son's age will be x+8 and father's age will be y+8=5/2(x+8) after solving you will get x = 8 and y = 32. Then after 16 years let father be n times of son's age i.e y + 16 = n(x + 16).
or 32 + 16 = n(8 + 16)
[putting x = 8 and y = 32]
or 48 = 24n,
or n = 2.
Therefore father is 2 times his son's age after 16 years.
or 32 + 16 = n(8 + 16)
[putting x = 8 and y = 32]
or 48 = 24n,
or n = 2.
Therefore father is 2 times his son's age after 16 years.
Arjun said:
7 years ago
Father age can be taken as x.
Son age is taken as y.
According to the first statement, father age is three times more than sons age at present is x=3y
According to the second statement after 8 years father age is 8 times more than the two and a half age of son age.
2*1/2 can be written as 5/2.
So, x+8=5/2y.
Substitute x=3y,
3y+8=5/2y,
3y-5/2y=-8,
1/2y=-8.
y=-16 after 8 years.
After 8 years father age is twice than son age.
Then after 16 years also twice than son ager.
Son age is taken as y.
According to the first statement, father age is three times more than sons age at present is x=3y
According to the second statement after 8 years father age is 8 times more than the two and a half age of son age.
2*1/2 can be written as 5/2.
So, x+8=5/2y.
Substitute x=3y,
3y+8=5/2y,
3y-5/2y=-8,
1/2y=-8.
y=-16 after 8 years.
After 8 years father age is twice than son age.
Then after 16 years also twice than son ager.
Aiswarya said:
7 years ago
As it is said that father's age is 3 times more than his son's.
So father's present age 3x and son's age x.
After 8 yrs their age will be,
3x+8 = 5/2(x + 8),
3x+8 = ((5x)/2) + (40/2),
2 * (3x+8) = 5x + 40,
6x + 16 = 5x + 40,
x = 24.
So son's age will be 24.
And father's age will be 3x = 72.
Further 8 more years ie; after 16 years,
Son's age will be x+16 ie; = 40,
and father's age will be 3x+16 ie; =88,
Therefore (x+16) ÷ (3+16) = 2.2.
So father's present age 3x and son's age x.
After 8 yrs their age will be,
3x+8 = 5/2(x + 8),
3x+8 = ((5x)/2) + (40/2),
2 * (3x+8) = 5x + 40,
6x + 16 = 5x + 40,
x = 24.
So son's age will be 24.
And father's age will be 3x = 72.
Further 8 more years ie; after 16 years,
Son's age will be x+16 ie; = 40,
and father's age will be 3x+16 ie; =88,
Therefore (x+16) ÷ (3+16) = 2.2.
Khan said:
10 years ago
Now review this Concept if you absorb it. It will be very helpful,
3:1.
5:2.
As the above ratio is not proportion so to proportionate it.
(3:1)*3 => 9:3.
(5:2)*2 => 10:4.
(9-10) = 1 but actual its 8 year difference.
Hence x = 8.
Now multiply 8 to the above ratio (not the original one but after proportionate one) and get answer.
It seems lengthy but it hardly take 1 minute to get answer hope you enjoy, ask me in detail if any.
3:1.
5:2.
As the above ratio is not proportion so to proportionate it.
(3:1)*3 => 9:3.
(5:2)*2 => 10:4.
(9-10) = 1 but actual its 8 year difference.
Hence x = 8.
Now multiply 8 to the above ratio (not the original one but after proportionate one) and get answer.
It seems lengthy but it hardly take 1 minute to get answer hope you enjoy, ask me in detail if any.
Vineshgujjari said:
1 decade ago
To all,
1)let ronit age be-> x,
2)father age be-> 3x+x,(as it is said 3 times more than ronit so 3x+x)
3)now it is said dat after 8 years,the father age will be two and half times ronit that is
father+8=5/2(ronit+8)
3x+x+8=5/2(x+8)
(4x+8)2=5(x+8)
8x+16=5x+40
3x=24
x=8.------(1)
4)again after 8 yrs,
x+3x+8+8=y(x+8+8)
4x+16=y(x+16)
now put x=8(from 1)
4*8+16=y(8+16)
32+16=y(24)
48=y(24)
Y=2.(hence solved)
Hope you all understand...
1)let ronit age be-> x,
2)father age be-> 3x+x,(as it is said 3 times more than ronit so 3x+x)
3)now it is said dat after 8 years,the father age will be two and half times ronit that is
father+8=5/2(ronit+8)
3x+x+8=5/2(x+8)
(4x+8)2=5(x+8)
8x+16=5x+40
3x=24
x=8.------(1)
4)again after 8 yrs,
x+3x+8+8=y(x+8+8)
4x+16=y(x+16)
now put x=8(from 1)
4*8+16=y(8+16)
32+16=y(24)
48=y(24)
Y=2.(hence solved)
Hope you all understand...
Anuj rojlove said:
1 decade ago
Consider son's age as 'x'.
So they have said,
Father is aged three times more than his son.
As per the statement, x+3x.
After 8 years, he would be 2 and a half times of his son.
So, x+3x+8 = x+8.
4x+8 = x+8.
(4x+8) = 5/2(x+8).
We get, 8x+16 = 5x+40 => 3x = 24.
x = 8.
After further 8 years,
So add 8 to the equation 4x+8+8 = x+8+8.
4x+16 = x+16.
So the ratio is, (4x+16)/(x+16) = 48/24.
=> 2 years.
Got it friends. Its simple?
So they have said,
Father is aged three times more than his son.
As per the statement, x+3x.
After 8 years, he would be 2 and a half times of his son.
So, x+3x+8 = x+8.
4x+8 = x+8.
(4x+8) = 5/2(x+8).
We get, 8x+16 = 5x+40 => 3x = 24.
x = 8.
After further 8 years,
So add 8 to the equation 4x+8+8 = x+8+8.
4x+16 = x+16.
So the ratio is, (4x+16)/(x+16) = 48/24.
=> 2 years.
Got it friends. Its simple?
Prasanna said:
1 decade ago
Let us assume father age is x.
G. T father age is 3 times greater than rohit age so (x+3x) = 4x.
G. T after 8 years he would be two and half times of ronit's age so 2 (1\2) = 5\2 (2*2+1) /2.
After further 8 years.
(4x+8) = 5/2 (x+8).
8x+16 = 5x+40.
8x-5x = 40-16.
3x = 24.
x = 8.
After further 8 years.
(4x+8) = (x+8).
Add 8 then.
(4x+8+8) = (x+8+8).
(4x+16) = (x+i6).
Required ratio = (4x+16)/(x+16) = 48/24 = 2 (sub x=8).
G. T father age is 3 times greater than rohit age so (x+3x) = 4x.
G. T after 8 years he would be two and half times of ronit's age so 2 (1\2) = 5\2 (2*2+1) /2.
After further 8 years.
(4x+8) = 5/2 (x+8).
8x+16 = 5x+40.
8x-5x = 40-16.
3x = 24.
x = 8.
After further 8 years.
(4x+8) = (x+8).
Add 8 then.
(4x+8+8) = (x+8+8).
(4x+16) = (x+i6).
Required ratio = (4x+16)/(x+16) = 48/24 = 2 (sub x=8).
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