Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
319 comments Page 31 of 32.
Sachin said:
8 years ago
Answer is 2.2 = 2 1/5.
Shantha said:
2 decades ago
How you got 5/2(x+8)?
Vamsidhar said:
5 years ago
How come 4x? Explain.
Parveen said:
1 decade ago
It is very helpful.
Gautam Negi said:
1 decade ago
Thanks a lot guys.
Vaishnavi said:
8 years ago
How that 5/2 came?
Vinod said:
1 decade ago
Thank you vaishu.
Priyanka said:
1 decade ago
How is come x+16?
Randy orton said:
9 years ago
How this 5/2 got?
Karan said:
1 decade ago
@Ravee superb.
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