Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
319 comments Page 32 of 32.
Haritham said:
1 decade ago
How it is 4x ?
KP Karthick said:
10 years ago
How you get 5?
Nishu said:
8 years ago
Thanks @Vivek.
Shivani said:
1 decade ago
How 5/2 come?
Hmdeep said:
1 decade ago
Thanks Jwala.
Parul said:
1 decade ago
How (x+8) ?
Vinoth said:
2 decades ago
How 4x ?
Poonam said:
2 decades ago
How 5/2?
Dharanisree said:
6 years ago
How 5/2?
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