Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
319 comments Page 30 of 32.
Rishi said:
6 years ago
Thanks for the explanation.
DINESH REDDY said:
1 decade ago
Ya 4x is absolutely right.
Ibbu said:
1 decade ago
Where is 5\2 coming from?
Sharad said:
7 years ago
How last step 4x+16/x+16?
Manmeet said:
5 years ago
The answer should be 2.5.
Ashwini said:
1 decade ago
Thanks for explanation.
Bhargav kolluru said:
8 years ago
Why should we take 5\2?
M. Sallah said:
8 years ago
Well explained. Thanks.
Arru said:
2 decades ago
How you got 5/2 (x+8)?
Laxmipriya said:
9 years ago
Why will we add 8 + 8?
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