Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
325 comments Page 29 of 33.
Javed patel said:
8 years ago
@Sonam.
3 is the correct answer.
3 is the correct answer.
Rohan said:
8 years ago
Can't we take 2.5 instead of 5/2?
Swaraj said:
7 years ago
How 5/2 came? Can anyone explain.
Akshay said:
6 years ago
How 48/24 came?
Please tell me.
Please tell me.
Bibek said:
4 years ago
It should be 3x + 8 = 5/2 (x+8).
(7)
Bibek said:
4 years ago
It should be 3x + 8 = 5/2 (x+8).
(4)
Aswini kumar Jena said:
2 months ago
How to add 8 more in a 16 ratio?
(2)
Vasu said:
2 decades ago
How this 8X+16 and 5x+40 came?
Suhail said:
8 years ago
How comes 5/2? please explain.
Waghmare Jaydip said:
7 years ago
Hot come 5/2? Please tell me.
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