Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
319 comments Page 27 of 32.
Nishu said:
8 years ago
Thanks @Vivek.
Sandeep said:
8 years ago
Hi, guys, in question itself says that father age is more than 3times of his son then x+3x is correct.
SHIV said:
8 years ago
How the ratio be 4x+16/x+8?
It should be 4x+8/x+8.
It should be 4x+8/x+8.
Amy said:
8 years ago
Because it is asked to find out how many times would his father be of Ronith's age?
Vaishnavi said:
8 years ago
How that 5/2 came?
Ashish said:
8 years ago
How (4x+16)/(x+16) = 48/24 came?
Please explain.
Please explain.
Kamesh said:
8 years ago
First, we think Rohit age is x, equation given for after 8 years. And at the end the question is further 8 years it means x+8+8=x+16 same way for father also.
Pavithra H L said:
8 years ago
Thanks for the explanation @Jwala.
M. Sallah said:
8 years ago
Well explained. Thanks.
Farhad said:
8 years ago
5/2=age of two and half=2+1/2=5/2.
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