Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
322 comments Page 26 of 33.
Akash said:
5 years ago
@Gauri.
Because 8 Years+ 8 Years =16 Years.
Because 8 Years+ 8 Years =16 Years.
Deepak verma said:
1 decade ago
Why we are taking ratio at end of solution?
Dhanu said:
1 decade ago
Any other short way to solve this question?
Meera said:
2 decades ago
Hi, Please explain the last step of ratio.
Shushant mishra said:
9 years ago
@Rekha.
2 and half times means 5/2 times.
2 and half times means 5/2 times.
Dimple said:
1 decade ago
Acc to me 5/2 multiplied on fathers side?
Stella said:
1 decade ago
Thank you friends for your explanations.
Yalleswari said:
9 years ago
How required ratio 4x + 16/x + 16 come?
Rekha thakur said:
9 years ago
How you are getting 5/2?
Which has 1/2?
Which has 1/2?
Mohit patil said:
1 year ago
How come 16 here? Anyone, Explain to me.
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