Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
322 comments Page 27 of 33.
Ratikant said:
2 decades ago
Please explain the last step of ratio.
Aadi said:
1 decade ago
Really nice explanation! good work. :)
Prashant said:
7 years ago
How this ratio came into picture 4x+8?
Madhu said:
2 years ago
Why 5/2 is used? Please explain to me.
(13)
Ganesh Lokhande said:
2 years ago
Why 5/2 is used? Please explain to me.
(29)
Kishan said:
9 years ago
@Maqsood nice explanation. Thank you.
Preethi said:
2 decades ago
How you got ratio (4x+16) / (x+16) ?
Affrin said:
1 decade ago
THANKS. Vaishu for your explanation.
Chandu said:
1 decade ago
THANKQ. Vaishu for your explanation.
Gauri_ said:
5 years ago
Why 16 is added? Explain in detail.
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