Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
319 comments Page 25 of 32.
John said:
7 years ago
How come 4x+16/x+16 = 48/24? Anyone explain me.
Shraddha said:
6 years ago
(4x+8) = 5/2(X+8).
= 8x+16 = 5x+40 how it came?
= 8x+16 = 5x+40 how it came?
Chinnu said:
3 years ago
Anyone, Can you explain this sum by taking 2.5?
Thara said:
1 decade ago
I can't understand this question how 5/2 came?
Rudra said:
1 decade ago
Thanx vaishu for your answer of the last step
Rajdip Kumar Dora said:
1 year ago
How it's 16 years? Can anyone please explain?
(5)
Stark said:
5 years ago
I got the answer as two and one-fifth times.
Akash said:
5 years ago
@Gauri.
Because 8 Years+ 8 Years =16 Years.
Because 8 Years+ 8 Years =16 Years.
Deepak verma said:
1 decade ago
Why we are taking ratio at end of solution?
Dhanu said:
1 decade ago
Any other short way to solve this question?
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