Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
322 comments Page 24 of 33.
Karthik said:
2 years ago
x = 3+y,
x = 5/2y,
5/2 = 3+y,
y = 5/2 - 3.
y = 2.5.
x = 5/2y,
5/2 = 3+y,
y = 5/2 - 3.
y = 2.5.
(9)
Abhiruchi said:
1 decade ago
How (4x+16) / (x+16) is = 48/24 ?
Please explain.
Please explain.
Minal said:
1 decade ago
Hi,
See two and half means 2*1/2
So 2*2+1 = 5/2.
See two and half means 2*1/2
So 2*2+1 = 5/2.
Manoj said:
1 decade ago
@durgesh. Your explanation is very good. Nice one.
Ammulu said:
9 years ago
Thanks @Vaishu. You explained it very clearly. :).
Ismail said:
9 years ago
Your clarification is very simple, Thanks @Vaishu.
Krithika said:
2 decades ago
It is explained 3 times more than his son. so 4x.
M.karthik said:
1 decade ago
How (4x+16) / (x+16) is = 48/24.
Please explain.
Please explain.
Alok said:
1 decade ago
Is there any other method to solve this question?
Ashish said:
8 years ago
How (4x+16)/(x+16) = 48/24 came?
Please explain.
Please explain.
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