Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
319 comments Page 21 of 32.
Ajay said:
1 decade ago
Can anyone say how the term 5/2(x=8)comes in the 2nd part please ?
Chinnu said:
3 years ago
If we take 2.5 or 5/2 will we get the same answer? Anyone explain.
Md haroon said:
9 years ago
I can't understand this problem please someone help me to get it.
Bharani said:
1 decade ago
@Newbie.
You made a wrong calculation 3*16 = 48 and 52+16 = 68.
You made a wrong calculation 3*16 = 48 and 52+16 = 68.
Seema said:
1 decade ago
Can any one tell help me to solve (4x+16) / (x+16) this problem?
Chandan debnath said:
10 years ago
What is that? Father's age is 3 times of Ronit so is it came 4x?
Janmaijay said:
6 years ago
How two and a half times can be written like 5/2 it must be 2/5?
Nandish said:
1 decade ago
(4x + 8) = 5 (x + 8)
2
8x + 16 = 5x + 40
how this 16 came
2
8x + 16 = 5x + 40
how this 16 came
Akhila said:
1 decade ago
Why this last step = (4x+8+8)/(x+8+8) should be divisible only?
Jaee said:
1 decade ago
In last step why the equations are divided? Why ratio is taken?
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