Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
2 times
1 times
2
3 times
4
3 times
Answer: Option
Explanation:

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

(4x + 8) = 5 (x + 8)
2

8x + 16 = 5x + 40

3x = 24

x = 8.

Hence, required ratio = (4x + 16) = 48 = 2.
(x + 16) 24

Discussion:
322 comments Page 22 of 33.

Jaee said:   1 decade ago
In last step why the equations are divided? Why ratio is taken?

Pratiksha said:   5 years ago
@All.

Here father age is 3times so the last equation is wrong.

Unknown said:   1 year ago
How ratio be calculated in this question? Please explain to me.
(3)

Satyam said:   1 decade ago
How the ratio b 4x+16\x+8 ?

It should be 4x+8\x+8 is correct.

Prateek said:   3 months ago
4x + 8 = 2.5x + 20.
1.5x = 12,
x = 12/1.5
x = 8.
24/48 = 1/2.

Poonam said:   2 decades ago
How the ratio b 4x+16\x+8 ?
It should be 4x+8\x+8 is correct

Sheela said:   2 decades ago
Its 3x + x = 4x. Because its 3 times more not only 3 times.

Nagarjun said:   1 decade ago
Thank you vaishu. I am satisfied after reading your answer.

Leenus said:   1 decade ago
I can't understand the last step can you please explain it.

Vinaya kumari said:   9 years ago
Hi friends,

It's three times more that, that is 3x not 4x.


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