Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
319 comments Page 22 of 32.
Pratiksha said:
5 years ago
@All.
Here father age is 3times so the last equation is wrong.
Here father age is 3times so the last equation is wrong.
Unknown said:
1 year ago
How ratio be calculated in this question? Please explain to me.
(3)
Satyam said:
1 decade ago
How the ratio b 4x+16\x+8 ?
It should be 4x+8\x+8 is correct.
It should be 4x+8\x+8 is correct.
Poonam said:
2 decades ago
How the ratio b 4x+16\x+8 ?
It should be 4x+8\x+8 is correct
It should be 4x+8\x+8 is correct
Sheela said:
1 decade ago
Its 3x + x = 4x. Because its 3 times more not only 3 times.
Nagarjun said:
1 decade ago
Thank you vaishu. I am satisfied after reading your answer.
Leenus said:
1 decade ago
I can't understand the last step can you please explain it.
Vinaya kumari said:
9 years ago
Hi friends,
It's three times more that, that is 3x not 4x.
It's three times more that, that is 3x not 4x.
Gauri said:
1 decade ago
thanks vaishu, for solving the problem for the last ratio
Vinitha said:
10 years ago
Any shortcut to solve this type of problem? please share.
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