Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
2 times
1 times
2
3 times
4
3 times
Answer: Option
Explanation:

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

(4x + 8) = 5 (x + 8)
2

8x + 16 = 5x + 40

3x = 24

x = 8.

Hence, required ratio = (4x + 16) = 48 = 2.
(x + 16) 24

Discussion:
319 comments Page 20 of 32.

Vignesh said:   9 years ago
I didn't understand the last step of the explanation. Please clarify me.

Kanwal,akhil said:   2 decades ago
Kritika, Sundar are absolutely correct. Read the statements correctly.

Sara shree said:   1 decade ago
I think we should take father's age be y.
So x+8 is equal to (3y+8)5/2

Nihal said:   1 decade ago
What is the meaning of last line of Question?

And how it is resolved?

Gaurav mahajan said:   1 decade ago
I want to something why we divided in the last step by 4x+16/x+16 = 2.

Shab said:   9 years ago
Why can't be father' age (x + 3)?

Why it should be taken as (x + 3x)?

Bhoomika said:   1 decade ago
How do we get (4x + 16) divide by (x + 16) instead of (4x+16)=(x+16)?

ManjulaPriya said:   1 decade ago
2 and a half means 2*1/2 is simplified 2*2=4, and 4+1=5 is come 5/2.

Aritra said:   1 decade ago
For all those who have a doubt how 5/2 came.

2+1/2 = 4/2+1/2 = 5/2.

Waqas Raza said:   6 years ago
Couldn't understand (4x+16/ x+16) = 2? what's the logic behind this?


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