Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
2 times
1 times
2
3 times
4
3 times
Answer: Option
Explanation:

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

(4x + 8) = 5 (x + 8)
2

8x + 16 = 5x + 40

3x = 24

x = 8.

Hence, required ratio = (4x + 16) = 48 = 2.
(x + 16) 24

Discussion:
319 comments Page 19 of 32.

Mahesh said:   2 decades ago
It is specified in the problem father age two and a half times of ronit's age.

Rebecca said:   5 years ago
Why do we have to add 8 to 5/2 of x yet it was after 8 years?

So, 4x+8 =5x/2.

Indu said:   1 decade ago
If father's present age 37 year then what's the age of son ? please help me.

Darshana said:   1 decade ago
How you got ratio (4x+16)/(x+16) ?

Can you explain the last step of ratio.

Shanmu said:   1 decade ago
How you got ratio (4x+16) / (x+16) ?
can u explain the last step of ratio.

Ashok said:   6 years ago
How you got ratio (4x+16)/(x+16)?

Can you explain the last step of ratio?

Mani said:   2 years ago
In the question, son's age is 2 (1/2) age.

So, 2x1/2 is 5/2fraction form.
(18)

Sowndariya said:   1 decade ago
Please explain the concept of solving this problem using shortcut method.

Srikanth said:   1 decade ago
5/2 (x+8) ? Can anybody please explain me why this expression has used?.

Sreeranga said:   1 decade ago
(4x + 8) = 2.5(x + 8).

4x + 8 = 2.5x + 20 and equation multiplied by 2.


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