Aptitude - Problems on Ages - Discussion

Hi friends,

Let son"s age is =1 then father age=4
which means ratio between father to son= 4 :1 (say f: s)........[1]
after 8 years this ratio = 2.5 : 1 ( f :s)
= 5:2...................[2]

but one thing is clear that difference betwwen father age and son age will always be same.


In eq. [1] difference is 3 and in [2] is 3 as it shuld be.

Now take a look at fther age .............it was 4 and after 8 years it is 5 ...it means in our values
I
n the ratio 1=8,
so ........................5=40(father age after 8 years)
and.......................2=16(son age after 8 years )

Hence after further 8 years later father age =40+8 =48 years and
................. son age = 16+8= 24

So ratio = 48:24
=2:1

@Ravee superb.

Ravee too good explanation.

@durgesh. Your explanation is very good. Nice one.

Thanks vaishu I understood your explanation clearly.

THANKQ. Vaishu for your explanation.

Try this way now the ratio is

4: 1
8 (4x2)=8 8-5=3x=8(5-2)
5 :2 5x1)=5 x=8
32 8 after 8 yrs 40 16 further 8 yrs 48 24 2;1

It is very helpful.

Is thare any shortcut to solve this in seconds.

To all,

1)let ronit age be-> x,
2)father age be-> 3x+x,(as it is said 3 times more than ronit so 3x+x)
3)now it is said dat after 8 years,the father age will be two and half times ronit that is
father+8=5/2(ronit+8)
3x+x+8=5/2(x+8)
(4x+8)2=5(x+8)
8x+16=5x+40
3x=24
x=8.------(1)
4)again after 8 yrs,
x+3x+8+8=y(x+8+8)
4x+16=y(x+16)
now put x=8(from 1)
4*8+16=y(8+16)
32+16=y(24)
48=y(24)
Y=2.(hence solved)

Hope you all understand...