Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
322 comments Page 11 of 33.
Cosmicguypradeep said:
1 decade ago
Simple
let the age of the son be "x"
father is aged 3 times more than his son so x+3x=4x
after 8 years,
4x+8=x+8....equation (1)
age will be 2 and half years i.e 2 1/2 = 5/2,
4x+8=5/2(x+8)
==> 8x+16=5x+40
==> x=8
after further 8 years;
4x+8+8=?(x+8+8)
4x+16=?(X+16)
==> ?=4x+16/x+16...equation (2)
==> substitute x=8 in eqution (2),
u will get ?=2
let the age of the son be "x"
father is aged 3 times more than his son so x+3x=4x
after 8 years,
4x+8=x+8....equation (1)
age will be 2 and half years i.e 2 1/2 = 5/2,
4x+8=5/2(x+8)
==> 8x+16=5x+40
==> x=8
after further 8 years;
4x+8+8=?(x+8+8)
4x+16=?(X+16)
==> ?=4x+16/x+16...equation (2)
==> substitute x=8 in eqution (2),
u will get ?=2
Arjun said:
1 decade ago
@Cosmicguypradeep
Let the age of the son be "x"
father is aged 3 times more than his son so x+3x=4x }(i agree this part)
after 8 years,
4x+8=x+8....equation (1)( doubt here q1: how X=4X that is how father age is equal to son age )
Let the age of the son be "x"
father is aged 3 times more than his son so x+3x=4x }(i agree this part)
after 8 years,
4x+8=x+8....equation (1)( doubt here q1: how X=4X that is how father age is equal to son age )
Stella said:
1 decade ago
Thank you friends for your explanations.
Ajay said:
1 decade ago
Can anyone say how the term 5/2(x=8)comes in the 2nd part please ?
Pankaj said:
1 decade ago
As the in statement state that fathers age would be 2 and 1/2 of the ronits ages.
Ronits age is x,
his fathers age is x+3x=4x,
after 8 yaers
(4x+8) = 2*1/2(x+8)
multiply 2*1/2 i.e (2*2+1)/2=5/2
4x+8 =5/2(x+8)
Ronits age is x,
his fathers age is x+3x=4x,
after 8 yaers
(4x+8) = 2*1/2(x+8)
multiply 2*1/2 i.e (2*2+1)/2=5/2
4x+8 =5/2(x+8)
Ashwini said:
1 decade ago
Thanks for explanation.
Shraddha said:
1 decade ago
As in question, fathers age is three times more than son's age. If we take sons age as x than father's age wll 3x how that 4x?
Subrata Hazra said:
1 decade ago
It is very much clear in the question first line that father is aged three times more than his son Ronit.
So simple is that if his sons age -x , then his age is x+3x = 4x
So simple is that if his sons age -x , then his age is x+3x = 4x
Ravee said:
1 decade ago
Hi Sharaddha here sum explansn to your doubt.
As you said Father's age is three times then son's age.
Here x or 1x both are same, I think you done this way.
"X", to this three times as 1x, 2x, 3x.
This way u'll get 3x, but we know X and 1X are same so.
To X (or 1X both are same) it is three times as 2x, 3x, 4x.
Now the F's age is X+3X=4X.
As you said Father's age is three times then son's age.
Here x or 1x both are same, I think you done this way.
"X", to this three times as 1x, 2x, 3x.
This way u'll get 3x, but we know X and 1X are same so.
To X (or 1X both are same) it is three times as 2x, 3x, 4x.
Now the F's age is X+3X=4X.
Shweta chaubey said:
1 decade ago
Son present age is =x
than father's present age is=more than 3 times of son age
=x+3x
According to the question,
after 8 years..
x+8=x+3x+8
x+8=4x+8
and father will be 5/2 greater than son
5/2(x+8)=4x+8
5x+40=8x+16
3x=24
x=8
ratio after 8 years
4x+8+8/x+8+8=6/3=2
than father's present age is=more than 3 times of son age
=x+3x
According to the question,
after 8 years..
x+8=x+3x+8
x+8=4x+8
and father will be 5/2 greater than son
5/2(x+8)=4x+8
5x+40=8x+16
3x=24
x=8
ratio after 8 years
4x+8+8/x+8+8=6/3=2
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