Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
2 times
1 times
2
3 times
4
3 times
Answer: Option
Explanation:

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

(4x + 8) = 5 (x + 8)
2

8x + 16 = 5x + 40

3x = 24

x = 8.

Hence, required ratio = (4x + 16) = 48 = 2.
(x + 16) 24

Discussion:
319 comments Page 12 of 32.

Vinaya kumari said:   9 years ago
Hi friends,

It's three times more that, that is 3x not 4x.

Nitesh kumar meena said:   9 years ago
Guys! It's three times more that mean 4x if it would be three times then we used 3x.

Shushant mishra said:   9 years ago
@Rekha.

2 and half times means 5/2 times.

Rekha thakur said:   9 years ago
How you are getting 5/2?

Which has 1/2?

Shushant mishra said:   9 years ago
Let the age of son be x then age of father will be 4x so we have ratio of father and son equals to 4x:x again after 8 years this becomes 5/2x:x as we all know that difference of age remains same then to make it same multiply above by 2 so that it becomes 5x:2x, therefore in 8 years 4x becomes 5x hence x is equal to 8 putting the value we get the age equal to 40 and 16 respectively and after 8 more years it will become 48 and 24 and hence father's age will be twice of son.

Ramesh said:   9 years ago
@Yalleswari.

As per the statement, x + 3x.
After 8 years, he would be 2 and a half times of his son.

So, x + 3x + 8 = x + 8.
4x + 8 = x + 8.
(4x + 8 ) = 5/2(x + 8).

We get, 8x + 16 = 5x + 40 => 3x = 24.
x = 8.

After further 8 years,

So add 8 to the equation 4x + 8 + 8 = x + 8+ 8.
4x + 16 = x + 16.

So the ratio is, (4x + 16)/(x + 16) = 48/24.
=> 2 years.

Yalleswari said:   9 years ago
How required ratio 4x + 16/x + 16 come?

Vignesh said:   9 years ago
You can also solve this problem by taking son's age as x and father's age as y. First, y = 4x as it is 3 times 'more' than that of his son. Then after 8 years son's age will be x+8 and father's age will be y+8=5/2(x+8) after solving you will get x = 8 and y = 32. Then after 16 years let father be n times of son's age i.e y + 16 = n(x + 16).

or 32 + 16 = n(8 + 16)
[putting x = 8 and y = 32]
or 48 = 24n,
or n = 2.

Therefore father is 2 times his son's age after 16 years.

Rahul said:   9 years ago
Anil got married 8 years ago. His present age is 6/5 times his age at the time of his marriage. Anil's sister was 10 years younger to him at the time of his marriage. The age of Anils sister is?

Solve this problem.
(1)

COOLCALM said:   9 years ago
Father F and Rohit R.
So, F = 3R + R = 4R.
After 8 years,
F + 8 = 2 1/2 (R + 8) means, F + 8 = 5/2 (R + 8).

So, 2(F + 8) = 5R + 40,
2(4R + 8) = 5R + 40,
8R + 16 = 5R + 40,
3R = 24,
R = 8.

Rohit's present age = 8 years.
After 16 years of present day (8 + 8).
Ratio would be F + 16/ R + 16.
So, 4R + 16/R + 16,
4(8) + 16/8 + 16 = 48/24 = 2.


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