Aptitude - Problems on Ages - Discussion

You can also solve this problem by taking son's age as x and father's age as y. First, y = 4x as it is 3 times 'more' than that of his son. Then after 8 years son's age will be x+8 and father's age will be y+8=5/2(x+8) after solving you will get x = 8 and y = 32. Then after 16 years let father be n times of son's age i.e y + 16 = n(x + 16).

or 32 + 16 = n(8 + 16)
[putting x = 8 and y = 32]
or 48 = 24n,
or n = 2.

Therefore father is 2 times his son's age after 16 years.

Anil got married 8 years ago. His present age is 6/5 times his age at the time of his marriage. Anil's sister was 10 years younger to him at the time of his marriage. The age of Anils sister is?

Solve this problem.

Father F and Rohit R.
So, F = 3R + R = 4R.
After 8 years,
F + 8 = 2 1/2 (R + 8) means, F + 8 = 5/2 (R + 8).

So, 2(F + 8) = 5R + 40,
2(4R + 8) = 5R + 40,
8R + 16 = 5R + 40,
3R = 24,
R = 8.

Rohit's present age = 8 years.
After 16 years of present day (8 + 8).
Ratio would be F + 16/ R + 16.
So, 4R + 16/R + 16,
4(8) + 16/8 + 16 = 48/24 = 2.

A is 2 years older than C and B is 2 years younger than C. The ratio of A's 6 years ago and B's 8 years ago is 6 : 5. Find C's present age.

It's so simple!

The value of x is ''8'' so 4 x is (4(8) + 16)/(8 + 16) and you get 48/24 = 2.

@Maqsood nice explanation. Thank you.

if Father is aged three times more than his son Ronit means, 3x + x = 4x then After 8 years, he would be two and a half times of Ronit's age.

In that above 'he' represent Ronit's father which means
(3x + 8) = 5/2(x + 8) right?

Then, how it will be (4x + 8) = 5/2(x + 8)?

How is it 4x? I didn't get it please tell me clearly.

I didn't understand the last step of the explanation. Please clarify me.

Your clarification is very simple, Thanks @Vaishu.