Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
322 comments Page 11 of 33.
Amy said:
8 years ago
Because it is asked to find out how many times would his father be of Ronith's age?
SHIV said:
8 years ago
How the ratio be 4x+16/x+8?
It should be 4x+8/x+8.
It should be 4x+8/x+8.
Sandeep said:
8 years ago
Hi, guys, in question itself says that father age is more than 3times of his son then x+3x is correct.
Nishu said:
8 years ago
Thanks @Vivek.
Rahul said:
8 years ago
Hi guys, how the problem is well segregate? Means where I place the proper place of future age. and present age? Please tell me.
Damo said:
8 years ago
For ratio sub 8 in x so we get (4(8)+16)÷(8+16)=2.
KARTHICK said:
8 years ago
5/2 simply how we can get 2 * 1/2 it implies 2*1/2=(4+1)1/2=>5/2.
The proper fraction will be used into the mixed fraction format.
The proper fraction will be used into the mixed fraction format.
Sachin said:
9 years ago
Answer is 2.2 = 2 1/5.
Bhargav kolluru said:
9 years ago
Why should we take 5\2?
Md haroon said:
9 years ago
I can't understand this problem please someone help me to get it.
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