Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 8)
8.
The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be:
12 years
14 years
18 years
20 years
Answer: Option
Explanation:

Let the present ages of son and father be x and (60 -x) years respectively.

Then, (60 - x) - 6 = 5(x - 6)

54 - x = 5x - 30

6x = 84

x = 14.

Son's age after 6 years = (x+ 6) = 20 years..

Discussion:
71 comments Page 6 of 8.

Shoeb said:   1 decade ago
Thank for making this sum so simple....

Shabana said:   1 decade ago
We can also solve as..
x = son age
y = father's age
x+y=60 -----(1)
(y-6)=5(x-6)-----(2)
by solving (1)&(2) we get x=14 ,y=46
after 6 yrs son age = x+6
= 14+6=20

Vijay said:   1 decade ago
Thank you so nice and easy.

Sowmya said:   2 decades ago
Thanks Amit.

Nandhini said:   1 decade ago
@Sunil.

Case I is right.
Logically father's age should be more than son's age.
So 4x is greater than x so its right to take son's age x and father's age 4x.


Case-II is logically wrong.
Let x=20 i.e father's age then
Son's age will be 80 i.e 4x.
How could a 20yrs father can have 80 yrs son.

Hence case - I is right sons age x and fathers age 4x.

Kirti said:   10 years ago
Father age = f, son age = s.

Then f+s = 60;

f+6 = 5(s+6).

On solving s = 6;

Then present age of son = s+6 = 6+6 = 12;

Then after 6 years it will be = 12+6 = 18;

What is wrong in that?

Zulminan Ahmed said:   10 years ago
Let father's age = X.

Let son's age = Y.

So, A/Q X+Y = 60 (Equation 1).

But six years ago father's age was five times the age of the son.

So, X-6 = 5(Y-6) (Equation 2).

Now putting the value of X = 60-Y from (Equation 1) in (Equation 2).

So, 60-Y-6 = 5(Y-6).

So the value of Y = 14.

But in question we have to find the son's age after 6 years so added 6 in 14. So, answer will be 20 years.

FINE!

Divya said:   10 years ago
I'm confused with this answer. I solve like this correct me if I'm wrong.

Let the present age of father = x.

Let the present age of son = y.

Sum of present age: x+y= 60 then equate will become: y = 60-x.

6 years ago the age of father will be 5 times the age of his son.

Father: x-6.
Son: y-6.

Equate these 2 equation, would become:

x-6 = 5(y-6).
x-6 = 5y-30.

By substituting the value y = 60-x:

x-6 = 5(60-x)-30.

x = 46 (present age of father).

Substitute the age of father to y = 60-x would gives us the present age of his son.

y = 60-46.

y = 14 (present age his son).

14 is my answer;

Thank you!

Avinash said:   1 decade ago
In previous sum + for ago in this this sum your using - for ago what we have to use say properly.

Somya khare said:   10 years ago
Son = x.
Father = y.

Then, x+y = 60.....(1).

6 years ago.

(y-6) = 5(x-6).

That is y-6 = 5x-30.

Therefore at present age we have y-6+6 = 5x-30+6.

That is, y = 5x-24.

From (1).

x+5x-24 = 60.
6x = 84.
x = 14.

Therefore after 6 years sons age will be.

14+6 = 20.


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