Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 8)
8.
The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be:
Answer: Option
Explanation:
Let the present ages of son and father be x and (60 -x) years respectively.
Then, (60 - x) - 6 = 5(x - 6)
54 - x = 5x - 30
6x = 84
x = 14.
Son's age after 6 years = (x+ 6) = 20 years..
Discussion:
71 comments Page 6 of 8.
Shoeb said:
1 decade ago
Thank for making this sum so simple....
Shabana said:
1 decade ago
We can also solve as..
x = son age
y = father's age
x+y=60 -----(1)
(y-6)=5(x-6)-----(2)
by solving (1)&(2) we get x=14 ,y=46
after 6 yrs son age = x+6
= 14+6=20
x = son age
y = father's age
x+y=60 -----(1)
(y-6)=5(x-6)-----(2)
by solving (1)&(2) we get x=14 ,y=46
after 6 yrs son age = x+6
= 14+6=20
Vijay said:
1 decade ago
Thank you so nice and easy.
Sowmya said:
2 decades ago
Thanks Amit.
Nandhini said:
1 decade ago
@Sunil.
Case I is right.
Logically father's age should be more than son's age.
So 4x is greater than x so its right to take son's age x and father's age 4x.
Case-II is logically wrong.
Let x=20 i.e father's age then
Son's age will be 80 i.e 4x.
How could a 20yrs father can have 80 yrs son.
Hence case - I is right sons age x and fathers age 4x.
Case I is right.
Logically father's age should be more than son's age.
So 4x is greater than x so its right to take son's age x and father's age 4x.
Case-II is logically wrong.
Let x=20 i.e father's age then
Son's age will be 80 i.e 4x.
How could a 20yrs father can have 80 yrs son.
Hence case - I is right sons age x and fathers age 4x.
Kirti said:
10 years ago
Father age = f, son age = s.
Then f+s = 60;
f+6 = 5(s+6).
On solving s = 6;
Then present age of son = s+6 = 6+6 = 12;
Then after 6 years it will be = 12+6 = 18;
What is wrong in that?
Then f+s = 60;
f+6 = 5(s+6).
On solving s = 6;
Then present age of son = s+6 = 6+6 = 12;
Then after 6 years it will be = 12+6 = 18;
What is wrong in that?
Zulminan Ahmed said:
10 years ago
Let father's age = X.
Let son's age = Y.
So, A/Q X+Y = 60 (Equation 1).
But six years ago father's age was five times the age of the son.
So, X-6 = 5(Y-6) (Equation 2).
Now putting the value of X = 60-Y from (Equation 1) in (Equation 2).
So, 60-Y-6 = 5(Y-6).
So the value of Y = 14.
But in question we have to find the son's age after 6 years so added 6 in 14. So, answer will be 20 years.
FINE!
Let son's age = Y.
So, A/Q X+Y = 60 (Equation 1).
But six years ago father's age was five times the age of the son.
So, X-6 = 5(Y-6) (Equation 2).
Now putting the value of X = 60-Y from (Equation 1) in (Equation 2).
So, 60-Y-6 = 5(Y-6).
So the value of Y = 14.
But in question we have to find the son's age after 6 years so added 6 in 14. So, answer will be 20 years.
FINE!
Divya said:
10 years ago
I'm confused with this answer. I solve like this correct me if I'm wrong.
Let the present age of father = x.
Let the present age of son = y.
Sum of present age: x+y= 60 then equate will become: y = 60-x.
6 years ago the age of father will be 5 times the age of his son.
Father: x-6.
Son: y-6.
Equate these 2 equation, would become:
x-6 = 5(y-6).
x-6 = 5y-30.
By substituting the value y = 60-x:
x-6 = 5(60-x)-30.
x = 46 (present age of father).
Substitute the age of father to y = 60-x would gives us the present age of his son.
y = 60-46.
y = 14 (present age his son).
14 is my answer;
Thank you!
Let the present age of father = x.
Let the present age of son = y.
Sum of present age: x+y= 60 then equate will become: y = 60-x.
6 years ago the age of father will be 5 times the age of his son.
Father: x-6.
Son: y-6.
Equate these 2 equation, would become:
x-6 = 5(y-6).
x-6 = 5y-30.
By substituting the value y = 60-x:
x-6 = 5(60-x)-30.
x = 46 (present age of father).
Substitute the age of father to y = 60-x would gives us the present age of his son.
y = 60-46.
y = 14 (present age his son).
14 is my answer;
Thank you!
Avinash said:
1 decade ago
In previous sum + for ago in this this sum your using - for ago what we have to use say properly.
Somya khare said:
10 years ago
Son = x.
Father = y.
Then, x+y = 60.....(1).
6 years ago.
(y-6) = 5(x-6).
That is y-6 = 5x-30.
Therefore at present age we have y-6+6 = 5x-30+6.
That is, y = 5x-24.
From (1).
x+5x-24 = 60.
6x = 84.
x = 14.
Therefore after 6 years sons age will be.
14+6 = 20.
Father = y.
Then, x+y = 60.....(1).
6 years ago.
(y-6) = 5(x-6).
That is y-6 = 5x-30.
Therefore at present age we have y-6+6 = 5x-30+6.
That is, y = 5x-24.
From (1).
x+5x-24 = 60.
6x = 84.
x = 14.
Therefore after 6 years sons age will be.
14+6 = 20.
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