Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 8)
8.
The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be:
12 years
14 years
18 years
20 years
Answer: Option
Explanation:

Let the present ages of son and father be x and (60 -x) years respectively.

Then, (60 - x) - 6 = 5(x - 6)

54 - x = 5x - 30

6x = 84

x = 14.

Son's age after 6 years = (x+ 6) = 20 years..

Discussion:
71 comments Page 1 of 8.

Amit said:   2 decades ago
We can also solve this as below:

Let six years ago son's age be x, and fathers age be 5x.

Then sum of their present age
(x+6)+(5x+6)=60
x+5x+12=60
6x+12=60
6x=60-12
6x=48
x=8

Hence six years ago son's age was 8 years
and present age is 8+6=14 years
Answer=after six years his age will be 14+6=20 years.
(2)

Sowmya said:   2 decades ago
Thanks Amit.

Vijay said:   1 decade ago
Thank you so nice and easy.

Shabana said:   1 decade ago
We can also solve as..
x = son age
y = father's age
x+y=60 -----(1)
(y-6)=5(x-6)-----(2)
by solving (1)&(2) we get x=14 ,y=46
after 6 yrs son age = x+6
= 14+6=20

Shoeb said:   1 decade ago
Thank for making this sum so simple....

Santosh said:   1 decade ago
Hey amit you already added 6 initially,
(x+6)+(5x+6)=60
x+5x+12=60
6x+12=60
6x=60-12
6x=48
x=8 and at end we haveto add another 6 means 8+6=14 years ....then how it would be 20 so actual answer is also wrong
(2)

Parthi said:   1 decade ago
Thank guys.

Sirisha said:   1 decade ago
@santosh

Amit is right. He taking as ago, present, after.

Pankaj said:   1 decade ago
Superb shabana keep it up.

Mrs pallavi said:   1 decade ago
Son's age= x, father's age is y.

x+y=60.........................(1)
as per 2nd statement
(y-6)=5(x-6)

5x-y=24........................(2)
therefore solving equ. 1 & 2
x=14 & y=46

3rd condition

Son age after 6 year
14+6= 20 year.


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