Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 8)
8.
The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be:
Answer: Option
Explanation:
Let the present ages of son and father be x and (60 -x) years respectively.
Then, (60 - x) - 6 = 5(x - 6)
54 - x = 5x - 30
6x = 84
x = 14.
Son's age after 6 years = (x+ 6) = 20 years..
Discussion:
71 comments Page 8 of 8.
Shafeen Ahmed said:
3 months ago
Solution using options:
6 years back Son's age: Minus 12 from each option.
So: 0 2 6 8.
6 years back sum of the father's and son's age = 60 - 6 - 6 = 48,
6 years back relationship of age; F = 5s.
If s = 8, F = 5 * 8 = 40;
Total = 40 + 8 = 48 (Verified).
After 6 years, son's age = 8 + 12 = 20.
6 years back Son's age: Minus 12 from each option.
So: 0 2 6 8.
6 years back sum of the father's and son's age = 60 - 6 - 6 = 48,
6 years back relationship of age; F = 5s.
If s = 8, F = 5 * 8 = 40;
Total = 40 + 8 = 48 (Verified).
After 6 years, son's age = 8 + 12 = 20.
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