Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 8)
8.
The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be:
12 years
14 years
18 years
20 years
Answer: Option
Explanation:

Let the present ages of son and father be x and (60 -x) years respectively.

Then, (60 - x) - 6 = 5(x - 6)

54 - x = 5x - 30

6x = 84

x = 14.

Son's age after 6 years = (x+ 6) = 20 years..

Discussion:
71 comments Page 5 of 8.

Yakesh said:   1 decade ago
Before(6 years back): 5x, x
Present:5x+6, x+6
After 6 years:5x+12,x+12
and 5x+6+x+6=60
x=8
after 6 years = x+12 = 8+12 = 20.

Appatakar said:   1 decade ago
Awesome pallavi thanks.

Manoj verma said:   1 decade ago
Suppose son's age=x father's age=y x+y=60 y-6=5(x-6) 60-x-6=5x-30 6x=84 x=14 after 6 years son's age=20

Priya said:   1 decade ago
Let s be son and f be father.
s+f=60
this was 6 years ago there fore
(s+f)-6=60-6 . . .here f=5s therfore substut
s+5s-6=54 . . .6s=60
therefor s=10
aftr 6 years
s=16

Please tell wats wrong with my logic.

Rajinder said:   1 decade ago
The sum of son and father's age can be written as
S+F=60 ----------(1)
before 6 years ago
5(S-6)=F-6
5S-30=F-6
5S-F=-6+30
5S-F=24 ----------(2)
ADDING (1) and (2),weget
6S=84
S=84/6=14
put s=14 in ist weget
F=46

Hence after 6 years Son;s age will be 14+6=20 years.

Jagadeesh said:   1 decade ago
Thanks pallavi.

Kauthik said:   1 decade ago
Father's age = x ; son's age = y

x+y = 60; x-6 = 5y; y+6 = ?

x = 5y+6

5y+6+y = 60

6y = 54

y = 9

Hence present age of son = y+6= 15.

I got answer like this. what's wrong in this method.

Pankaj said:   1 decade ago
Superb shabana keep it up.

Sirisha said:   1 decade ago
@santosh

Amit is right. He taking as ago, present, after.

Parthi said:   1 decade ago
Thank guys.


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