Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 8)
8.
The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be:
Answer: Option
Explanation:
Let the present ages of son and father be x and (60 -x) years respectively.
Then, (60 - x) - 6 = 5(x - 6)
54 - x = 5x - 30
6x = 84
x = 14.
Son's age after 6 years = (x+ 6) = 20 years..
Discussion:
71 comments Page 8 of 8.
Chandana said:
1 decade ago
I think so...
it's after 6 years,
in eqn x-6=5y u didnt reduced son's age to 6years(after 6years)
x-6=5(y-6)
then u get the answer..
x-6=5y-30
x=5y-24;
5y-24+y=60
6y=84
y=14
hence present age of son=y+6=20
it's after 6 years,
in eqn x-6=5y u didnt reduced son's age to 6years(after 6years)
x-6=5(y-6)
then u get the answer..
x-6=5y-30
x=5y-24;
5y-24+y=60
6y=84
y=14
hence present age of son=y+6=20
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