Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 15)
15.
The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:
5 : 2
7 : 3
9 : 2
13 : 4
Answer: Option
Explanation:

Let the ages of father and son 10 years ago be 3x and x years respectively.

Then, (3x + 10) + 10 = 2[(x + 10) + 10]

3x + 20 = 2x + 40

x = 20.

Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.

Discussion:
79 comments Page 3 of 8.

Gimid-pussi said:   6 years ago
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.

Anyone explain this step in detail.
(1)

Ramachandran said:   2 decades ago
@Ramu:
Now Assume Father age is x and Son age is y

According to first statement : Father's age is three years more than three times the son's age
x=3y+3
So x-3y=3 --->1

According to second statement : After three years, father's age will be ten years more than twice the son's age
x+3=2(y+3)+10
x-2y=13 ---->2

substitute 1 & 2:
x=33
y=10

So father's present age is 33.

Thank you god bless you all.

Vaishnavi said:   10 years ago
Express the following linear equation in two variables by talking present ages of his father and son as x and y respectively.

Age of father 5 years ago was two years more than 7 times the age of his son at that time.

Can anyone help me?

Aquarius said:   9 years ago
Guys, can anyone tell me about this problem?

Sushil was thrice as old as Snehal 6 years back. Sushil will be5/3 times as old as Snehal 6 years hence. How old is Snehal today?

Why can't we take Snehal Current age be x?
6yrs ago be x-6.
Sushil ag 6ysr ago be 3(x-6) of Snegal age.
6 yrs hence from current age Sushil be,
3(x-6)+6+6= 5/3(x)+6.
Is is the correct way?

Vic said:   1 decade ago
TO SOLVE BOTH THE EQUATIONS
3X+10=2X-10 WHERE X=20
SO PUT THE X VALUE IN PLACES OF X
WILL PRODUCE THE RATIO
70:30 i.e=7:3

Devendra said:   1 decade ago
All the trick are good but Malic trick is so, esy but one confusion here X=20 mens ago(back 10 year) &Hence(after 10yer) so.. 10+10 X=20.............

(3x+10):(x+10)=7:3........... Just put the value of X=20......

Mickey said:   1 decade ago
Present ages be
father = x
son = y

10 years ago,
father = x-10
son = y-10

a/q
(x-10)= 3(y-10)..........1

10 years hence,
father = x+10
son = y+10

a/q
(x+10)= 2(y+10).......2

We get x=70, y=30.

Mihir said:   1 decade ago
Can anybody tell the answer to this question?

In 1996, Raju age was equal to the numbers formed by the last two digits of his birth year. This was same for his grandfather also. Find the difference between their ages.

Paritosh said:   9 years ago
Let Akash age is x+4, Akansha age is x.

from the given relation 4x = 3(x+4)
now x=12,x+4=16
Their combined age is 12+16=28.

Namgay said:   9 years ago
Why to take 10 in order to find the present ratio?


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