Aptitude - Problems on Ages - Discussion

Ten years hence means ten years from present age or ten years from past.

@Arshad.

We can calculate from present age either hence or later and also ago, before, after in any age problems.

The age of the son and the father are in the ratio 3:10. If the father have 52 years, how old is the son?

Let's present ages of father and son will be x and y.
Before 10 yearss, it will be (x - 10) = 3(y - 10).

Ten years hence , the equation will be x + 10 = 2(y + 10).
Solve these two equations, we get x = 70 years and y =30 years.

Hi.

Let as consider
Father's age = x.
Son's age = y.

=> 10 year Ago Father's age is x - 10 = 3(y-10) -----> Equation 1.
=> After 10 years Father's age x + 10 = 2(y+10) ------> Equation 2.

Solve 2 equation......
=> x - 10 = 3y - 30.
x - 3y = - 20 --> Equation 3.
=> x - 2y = 10 --> New Equation 4.
=> Substract Equation 3 from Equation 4.
x - 3y = - 20
x - 2y = 10
----------------
- y = - 30.

So, y = 30 --> age of son.

Then put y =30 into any equation.

x - 2(30) = 10
x - 60 = 10.
x = 70 --> age of father.

x = 7.
y = 3.

I hope, this will help you.

In all these questions, we simply assuming son's age as x and father 's age as nx (n=number given).

And why in this question alone we are assuming son's age as x and father 's age as y.

Pleas say the difference.

I need an answer to this question and way of solving.

The present age of the father is four times of his son. When will the son be as old as a father now their ages will be 99 find their present ages?