Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 15)
15.
The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:
Answer: Option
Explanation:
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
Discussion:
77 comments Page 7 of 8.
Ramu said:
1 decade ago
Father's age is three years more than three times the son's age.After three years, father's age will be ten years more than twice the son's age. What is the father's present age.
Brindha said:
9 years ago
10 years ago,
Father age is = (3x - 10).
Son age = x.
10 years now.
Father age = 3x - 10 + 10 -------> (2).
Son age is 2 (x + 10) = 2x + 20 -------> (1).
1 = 2.
3x - 10 + 10 = 2x + 20.
x = 20.
Father age is = (3x - 10).
Son age = x.
10 years now.
Father age = 3x - 10 + 10 -------> (2).
Son age is 2 (x + 10) = 2x + 20 -------> (1).
1 = 2.
3x - 10 + 10 = 2x + 20.
x = 20.
Vamsee menda said:
1 decade ago
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10].
3x + 20 = 2x + 40.
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
Then, (3x + 10) + 10 = 2[(x + 10) + 10].
3x + 20 = 2x + 40.
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
Ankur said:
1 decade ago
Whats meaning of 10 years hence?
Neha gupta said:
1 decade ago
After 10 years from the present > Ankur.
EncodeMaster said:
1 decade ago
Let Father = F and Son = S.
10 Years Ago:
F-10 = 3(S-10).
F = 3S-20 ------ (i).
10 year hence:
F+10 = 2(S+10) ------ (ii).
Replace (i) in (ii).
3S-20+10 = 2S+20.
3S-10 = 2S+20.
S = 30 <----- Son's Age.
Again using (i).
F = 3(30)-20.
F = 70.
So Ratio is 70:30 ----> 7:3.
10 Years Ago:
F-10 = 3(S-10).
F = 3S-20 ------ (i).
10 year hence:
F+10 = 2(S+10) ------ (ii).
Replace (i) in (ii).
3S-20+10 = 2S+20.
3S-10 = 2S+20.
S = 30 <----- Son's Age.
Again using (i).
F = 3(30)-20.
F = 70.
So Ratio is 70:30 ----> 7:3.
Lakshmi said:
1 decade ago
What is the meaning of fathers age will be twice that of his son.
2(3x+10+10) = (x+10+10).
Why are you taking?
(3x+10+10) = 2((x+10)+10).
Please tell me.
2(3x+10+10) = (x+10+10).
Why are you taking?
(3x+10+10) = 2((x+10)+10).
Please tell me.
Javeed said:
1 decade ago
10 years ago means 3x - 10. But how it become 3x + 10?
Shubham said:
1 decade ago
Father's age is twice of his son's age. 8 years ago. He was thrice as old as his son. So what will be d son's age at present.
Anju said:
1 decade ago
@Javeed:
The age is calculating with respect to the present age. So ten years ago means 3x-10. So the present age will b 3x+10.
Now after ten years 3x+10+10.
The age is calculating with respect to the present age. So ten years ago means 3x-10. So the present age will b 3x+10.
Now after ten years 3x+10+10.
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