Aptitude - Problems on Ages - Discussion

Thanks to all. Now I got some idea.

Some time it good to solve question without any quick formula.

Thanks Mickey.

Can anybody tell me how to find the ratio?

Given, father's age(x) = 3(y)son's age.

y = x/3.

Original equation is, 10 years ago x-10 = 3(y-10).

= 3(x/3-10).....(A).

Given, after 10 years father's age(x) = 2(y)son's age.

y = x/2.

Original equation is, after 10 years x+10 = 2(y+10).

= 2(x/2+10).........(B).

Equating (A) & (B) for present ages, 3(x/3-10) = 2(x/2+10).

x = 80.

y = 40.

These are the ages after 10 years.

Hence, for present ages remove 10 years from both 70:30 or 7:3.

All the trick are good but Malic trick is so, esy but one confusion here X=20 mens ago(back 10 year) &Hence(after 10yer) so.. 10+10 X=20.............

(3x+10):(x+10)=7:3........... Just put the value of X=20......

Present ages be
father = x
son = y

10 years ago,
father = x-10
son = y-10

a/q
(x-10)= 3(y-10)..........1

10 years hence,
father = x+10
son = y+10

a/q
(x+10)= 2(y+10).......2

We get x=70, y=30.

Can anybody tell the answer to this question?

In 1996, Raju age was equal to the numbers formed by the last two digits of his birth year. This was same for his grandfather also. Find the difference between their ages.

Thanks nagu.

VERY TRICKY!!!!!!

@Ramu:
Now Assume Father age is x and Son age is y

According to first statement : Father's age is three years more than three times the son's age
x=3y+3
So x-3y=3 --->1

According to second statement : After three years, father's age will be ten years more than twice the son's age
x+3=2(y+3)+10
x-2y=13 ---->2

substitute 1 & 2:
x=33
y=10

So father's present age is 33.

Thank you god bless you all.