Aptitude - Problems on Ages - Discussion

Given, father's age(x) = 3(y)son's age.

y = x/3.

Original equation is, 10 years ago x-10 = 3(y-10).

= 3(x/3-10).....(A).

Given, after 10 years father's age(x) = 2(y)son's age.

y = x/2.

Original equation is, after 10 years x+10 = 2(y+10).

= 2(x/2+10).........(B).

Equating (A) & (B) for present ages, 3(x/3-10) = 2(x/2+10).

x = 80.

y = 40.

These are the ages after 10 years.

Hence, for present ages remove 10 years from both 70:30 or 7:3.

Son age is "x".
Father age is "3x".

10 year hence (after).
son age will become "x+10".
father age will become "3x+10" but father age is twice of son's age So it will become 2(x+10).


So, the equation will be.
(3x+10) = 2(x+10),
3x+10=2x+20,
3x-2x=20-10.
x=10.

For 10 years after age we need to add 10 in x (the most important).
x=10+10.
x=20.
Now, substitute the value of x in the x+10 equation.
Son age will become "x+10" => 20+10 = 30.
Father age will become "3x+10" => 3*20+10 = 70.

70/30 = 7/3 = 7:3.

Hi.

Let as consider
Father's age = x.
Son's age = y.

=> 10 year Ago Father's age is x - 10 = 3(y-10) -----> Equation 1.
=> After 10 years Father's age x + 10 = 2(y+10) ------> Equation 2.

Solve 2 equation......
=> x - 10 = 3y - 30.
x - 3y = - 20 --> Equation 3.
=> x - 2y = 10 --> New Equation 4.
=> Substract Equation 3 from Equation 4.
x - 3y = - 20
x - 2y = 10
----------------
- y = - 30.

So, y = 30 --> age of son.

Then put y =30 into any equation.

x - 2(30) = 10
x - 60 = 10.
x = 70 --> age of father.

x = 7.
y = 3.

I hope, this will help you.

10 years ago:

Son = x - 10,

Father = 3 (x - 10).

10 years hence:

Son = x + 10.

Father = 2 (x + 10).

Equating the age of the father at hence 10 years, so we have to add 20 in the past 10 years.

So,

3 (x - 10) + 20 = 2 (x + 10),

3x - 30 + 20 = 2x + 20,

3x - 2x = 30 - 20 + 20,

X = 30.

Now for present ratio, we will add 10 to past equation.

So,

3 (x - 10) + 10 : x - 10 + 10,

3 (30 - 10) +10 : 30 - 10 + 10,

3 (20) + 10 : 30 = 70 : 30,

7 : 3.

@Ramu:
Now Assume Father age is x and Son age is y

According to first statement : Father's age is three years more than three times the son's age
x=3y+3
So x-3y=3 --->1

According to second statement : After three years, father's age will be ten years more than twice the son's age
x+3=2(y+3)+10
x-2y=13 ---->2

substitute 1 & 2:
x=33
y=10

So father's present age is 33.

Thank you god bless you all.

Hi all,

There is no like we should subtract
We need to finish with simple way so

They are taking 10 years ago they boy age is x
Then the father's age is 3x

So now the age of boy and father is x+10 and 3x+10

So 10 years hence it will be x+10+10 and 3x+10+10

But as per problem fathers age is double than his son

So (3x + 10) + 10 = 2[(x + 10) + 10]

Hope this will help you. Have a nice day.!

Guys, can anyone tell me about this problem?

Sushil was thrice as old as Snehal 6 years back. Sushil will be5/3 times as old as Snehal 6 years hence. How old is Snehal today?

Why can't we take Snehal Current age be x?
6yrs ago be x-6.
Sushil ag 6ysr ago be 3(x-6) of Snegal age.
6 yrs hence from current age Sushil be,
3(x-6)+6+6= 5/3(x)+6.
Is is the correct way?

We can do this problem by this method:
let the age of the son be x
let the age of the father be y
10 years ago
x-10=y-10
father was 3times the son so,
3(x-10)=y-10
3x-30=y-10
3x-y=20........1 equation
10 years hence
x+10=y+10
father was 2times that of the son
2(x+10)=y+10
2x+20=y+10
2x-y=-10........2equation
now solve the equation 1 and 2.

Here is my solution;

Son's present age = x.
Father's present age=y.

10 years ago

(y-10) = 3(x-10)
y-10=3x-30
y-3x=-20 --------> eq 1


10 years after

(y+10)=2(x+10)
y+10=2x+20
y-2x=10 --------> eq2.

now

y-3x=-20,
y-2x=10.

10(y-3x)=-20(y-2x).
10y-30x=-20y+40x.
10y+20y=40x+30x.
30y=70x.
So now y:x = 3:7.

10 years ago : father age = thrice son ---> 3 x Son's age - 10(10 years ago) = father's age.

After 3 years : father age = twice son ---> 2 x Son's age + 10(after 10 years) = father's age.

So, ,
3S-10 : F = 2S+10 : F
3S-10=2S+10
S=20.

Substituting S value in 3S -10: 2S + 10.
We get 7:3.