Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 15)
15.
The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:
Answer: Option
Explanation:
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
Discussion:
79 comments Page 2 of 8.
Gimmeda Pussi said:
6 years ago
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
How are we supposed to arrive at this step? Please explain me.
How are we supposed to arrive at this step? Please explain me.
(2)
Shiva said:
1 decade ago
What is the meaning of fathers age will be twice that of his son?
2(3x + 10 + 10) = (x + 10 + 10).
Why are you taking?
(3x + 10 + 10) = 2((x + 10) + 10).
Please tell me.
2(3x + 10 + 10) = (x + 10 + 10).
Why are you taking?
(3x + 10 + 10) = 2((x + 10) + 10).
Please tell me.
(1)
Riya said:
1 month ago
@All.
Based on the given question.
Let's take 3x + 20/x + 20 = 2/1.
where x = 20.
therefore father'age is:3x = 3 * 20 = 60.
Son's age is; x = 20.
Add 10 for present age 60 + 10 = 70.
20 + 10 = 30.
The ratio of the present age is 70/30 = 7/3.
Based on the given question.
Let's take 3x + 20/x + 20 = 2/1.
where x = 20.
therefore father'age is:3x = 3 * 20 = 60.
Son's age is; x = 20.
Add 10 for present age 60 + 10 = 70.
20 + 10 = 30.
The ratio of the present age is 70/30 = 7/3.
(1)
Santash Kumar Jena said:
1 decade ago
10 years ago:
Son = x - 10,
Father = 3 (x - 10).
10 years hence:
Son = x + 10.
Father = 2 (x + 10).
Equating the age of the father at hence 10 years, so we have to add 20 in the past 10 years.
So,
3 (x - 10) + 20 = 2 (x + 10),
3x - 30 + 20 = 2x + 20,
3x - 2x = 30 - 20 + 20,
X = 30.
Now for present ratio, we will add 10 to past equation.
So,
3 (x - 10) + 10 : x - 10 + 10,
3 (30 - 10) +10 : 30 - 10 + 10,
3 (20) + 10 : 30 = 70 : 30,
7 : 3.
Son = x - 10,
Father = 3 (x - 10).
10 years hence:
Son = x + 10.
Father = 2 (x + 10).
Equating the age of the father at hence 10 years, so we have to add 20 in the past 10 years.
So,
3 (x - 10) + 20 = 2 (x + 10),
3x - 30 + 20 = 2x + 20,
3x - 2x = 30 - 20 + 20,
X = 30.
Now for present ratio, we will add 10 to past equation.
So,
3 (x - 10) + 10 : x - 10 + 10,
3 (30 - 10) +10 : 30 - 10 + 10,
3 (20) + 10 : 30 = 70 : 30,
7 : 3.
(1)
Yhxyc said:
9 years ago
Thanks everybody for the given explanation.
(1)
Shruti iyer said:
9 years ago
Akash said to Akansha when I will be 4 times your present age you will be 3 times my present age. If Akash is 4 years older than Akansha find the sum of their present ages?
Can anybody solve this with a shortcut method, please?
Can anybody solve this with a shortcut method, please?
(1)
Sanjay said:
9 years ago
Thanks for all the solution.
(1)
Paritosh said:
9 years ago
If we assume x=10,y=40,it satisfies the given condition And we get ratio as 5:2
is it correct?
is it correct?
(1)
Rohini Priya said:
8 years ago
Here they considered ages 10 years ago 3x and x, these are not present ages.
Since we solve all problems by having present ages we convert them to the present age.
So the present ages will be 3x+10 and x+10.
Since we solve all problems by having present ages we convert them to the present age.
So the present ages will be 3x+10 and x+10.
(1)
Pammy said:
7 years ago
@Archi simple why they have taken minus means 3x is 10 year ago.
3x+10 present age.
3x+10 +10 means 10 years after present age.
3x+10 present age.
3x+10 +10 means 10 years after present age.
(1)
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