Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 15)
15.
The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:
5 : 2
7 : 3
9 : 2
13 : 4
Answer: Option
Explanation:

Let the ages of father and son 10 years ago be 3x and x years respectively.

Then, (3x + 10) + 10 = 2[(x + 10) + 10]

3x + 20 = 2x + 40

x = 20.

Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.

Discussion:
77 comments Page 4 of 8.

Mannai shakthi said:   7 years ago
Please give detailed answer and explanation about this sum. How will add the ages when it is mentioned as ago?

Brindha said:   9 years ago
10 years ago,
Father age is = (3x - 10).
Son age = x.

10 years now.

Father age = 3x - 10 + 10 -------> (2).
Son age is 2 (x + 10) = 2x + 20 -------> (1).

1 = 2.

3x - 10 + 10 = 2x + 20.
x = 20.

SHUBHAM said:   7 years ago
Ago means subtract so, X+10-10 this statement may be right.

Rachana said:   6 years ago
@Shubham.

Actually, it is not right.
Because initially the age of the boy and his dad are 'x' & '3x' respectively.
10yrs ago it was the case.
Presently, their ages are (x+10) & (3x+10) respectively.

Manta said:   1 decade ago
Manish your method is looking very easy. But from where 20 has come?

Pankaj said:   1 decade ago
Thanks sheikh.

Sri said:   1 decade ago
Hi sheikh,

In the problem,10 yrs ago father was thrice his son means
x-10=3(y-10) but how 3(x-10)=y-10 ?

Sri said:   1 decade ago
If we take x-10=3(y-10) and x+10=2(y+10) or 3(x-10)=y-10 and 2(x+10)=y+10 also we are getting ratio as 7:3

Priya said:   1 decade ago
How you got the value as x=20 while solving this 2 equ x=30 is coming how if possible please solve that 2 equ please.

Mallik said:   1 decade ago
@Bharat

It is simple. Here we are considering for after 10 years but the question is to find ratio of the present age.

So, (3x+10):(x+10) as x=20

Subs in the above equation, You will get 7:3.


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