Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 15)
15.
The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:
Answer: Option
Explanation:
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
Discussion:
79 comments Page 4 of 8.
Mannai shakthi said:
8 years ago
Please give detailed answer and explanation about this sum. How will add the ages when it is mentioned as ago?
Iba Krish said:
8 years ago
Very useful @Nagu.
Suren said:
2 decades ago
Thanks nagu.
SHUBHAM said:
8 years ago
Ago means subtract so, X+10-10 this statement may be right.
Rachana said:
7 years ago
@Shubham.
Actually, it is not right.
Because initially the age of the boy and his dad are 'x' & '3x' respectively.
10yrs ago it was the case.
Presently, their ages are (x+10) & (3x+10) respectively.
Actually, it is not right.
Because initially the age of the boy and his dad are 'x' & '3x' respectively.
10yrs ago it was the case.
Presently, their ages are (x+10) & (3x+10) respectively.
Manish said:
2 decades ago
VERY TRICKY!!!!!!
Ankit said:
10 years ago
5 years ago, the sum of ages of father and his son was 30 years. 3 years hence the sum of their ages would be?
Can anyone answer it?
Can anyone answer it?
Ramu said:
2 decades ago
Father's age is three years more than three times the son's age.After three years, father's age will be ten years more than twice the son's age. What is the father's present age.
Manta said:
2 decades ago
Manish your method is looking very easy. But from where 20 has come?
Pankaj said:
2 decades ago
Thanks sheikh.
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