Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 15)
15.
The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:
Answer: Option
Explanation:
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
Discussion:
77 comments Page 4 of 8.
Mannai shakthi said:
7 years ago
Please give detailed answer and explanation about this sum. How will add the ages when it is mentioned as ago?
Archi said:
2 decades ago
For 10 years ago it should be minus 10 give me reason please ?
SHUBHAM said:
7 years ago
Ago means subtract so, X+10-10 this statement may be right.
Rachana said:
6 years ago
@Shubham.
Actually, it is not right.
Because initially the age of the boy and his dad are 'x' & '3x' respectively.
10yrs ago it was the case.
Presently, their ages are (x+10) & (3x+10) respectively.
Actually, it is not right.
Because initially the age of the boy and his dad are 'x' & '3x' respectively.
10yrs ago it was the case.
Presently, their ages are (x+10) & (3x+10) respectively.
Pankaj said:
1 decade ago
Thanks sheikh.
Sri said:
1 decade ago
Hi sheikh,
In the problem,10 yrs ago father was thrice his son means
x-10=3(y-10) but how 3(x-10)=y-10 ?
In the problem,10 yrs ago father was thrice his son means
x-10=3(y-10) but how 3(x-10)=y-10 ?
Sri said:
1 decade ago
If we take x-10=3(y-10) and x+10=2(y+10) or 3(x-10)=y-10 and 2(x+10)=y+10 also we are getting ratio as 7:3
Priya said:
1 decade ago
How you got the value as x=20 while solving this 2 equ x=30 is coming how if possible please solve that 2 equ please.
Mallik said:
1 decade ago
@Bharat
It is simple. Here we are considering for after 10 years but the question is to find ratio of the present age.
So, (3x+10):(x+10) as x=20
Subs in the above equation, You will get 7:3.
It is simple. Here we are considering for after 10 years but the question is to find ratio of the present age.
So, (3x+10):(x+10) as x=20
Subs in the above equation, You will get 7:3.
Sheikh Moinuddin said:
1 decade ago
We can do this problem by this method:
let the age of the son be x
let the age of the father be y
10 years ago
x-10=y-10
father was 3times the son so,
3(x-10)=y-10
3x-30=y-10
3x-y=20........1 equation
10 years hence
x+10=y+10
father was 2times that of the son
2(x+10)=y+10
2x+20=y+10
2x-y=-10........2equation
now solve the equation 1 and 2.
let the age of the son be x
let the age of the father be y
10 years ago
x-10=y-10
father was 3times the son so,
3(x-10)=y-10
3x-30=y-10
3x-y=20........1 equation
10 years hence
x+10=y+10
father was 2times that of the son
2(x+10)=y+10
2x+20=y+10
2x-y=-10........2equation
now solve the equation 1 and 2.
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