Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 6)
6.
A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
Answer: Option
Explanation:
Let the son's present age be x years. Then, man's present age = (x + 24) years.
(x + 24) + 2 = 2(x + 2)
x + 26 = 2x + 4
x = 22.
Discussion:
95 comments Page 2 of 10.
Koteswararao chimmili said:
9 years ago
Son age x,
Father age x + 24,
(x + 24) = x -----------> equation 1.
After two year mean
[A]. 14 years + 2 = 16
[B]. 18 years + 2 = 20
[C]. 20 years + 2 = 22
[D]. 22 years + 2 = 24
Substitute [A].14 years + 2 = 16 in equation 1
(x + 24) = x
16 + 24 = 16
40 = 16 ( false ).
Substitute [B].18 years + 2 = 20 in equation 1.
(x + 24) = x
20 + 24 = 20
44 = 20 ( false ).
Substitute [C].20 years + 2 = 22 in equation 1.
(x + 24) = x
22 + 24 = 22
46 = 22 (false).
Substitute [D].22 years + 2=24 in equation 1.
(x + 24) = x
24 + 24 = 24
48 = 24
2[24] = 24 (true).
His age will be twice the age of his son.
So, the answer is Option D.
Father age x + 24,
(x + 24) = x -----------> equation 1.
After two year mean
[A]. 14 years + 2 = 16
[B]. 18 years + 2 = 20
[C]. 20 years + 2 = 22
[D]. 22 years + 2 = 24
Substitute [A].14 years + 2 = 16 in equation 1
(x + 24) = x
16 + 24 = 16
40 = 16 ( false ).
Substitute [B].18 years + 2 = 20 in equation 1.
(x + 24) = x
20 + 24 = 20
44 = 20 ( false ).
Substitute [C].20 years + 2 = 22 in equation 1.
(x + 24) = x
22 + 24 = 22
46 = 22 (false).
Substitute [D].22 years + 2=24 in equation 1.
(x + 24) = x
24 + 24 = 24
48 = 24
2[24] = 24 (true).
His age will be twice the age of his son.
So, the answer is Option D.
(1)
Chetan said:
1 decade ago
A man is 24 years older than his son.
Let us take son's age as X. So, father's age will be X+24.
In two years, son's age X+2.
Father's age X+24+2 = X+26.
His (Father's) age will be twice the age of his son.
X+26 = 2(X+2) (Twice the age of his son. So twice Son's age).
X+26 = 2X+4.
22 = X.
By solving, X = 22.
Let us take son's age as X. So, father's age will be X+24.
In two years, son's age X+2.
Father's age X+24+2 = X+26.
His (Father's) age will be twice the age of his son.
X+26 = 2(X+2) (Twice the age of his son. So twice Son's age).
X+26 = 2X+4.
22 = X.
By solving, X = 22.
(1)
Vetri said:
7 years ago
I think 20 is the correct answer.
(1)
Shahee said:
8 years ago
Why can't we take father's age is 24x instead of 24+x. Can anyone explain?
(1)
NIJEESH V S said:
6 years ago
@Ranjani cleared my doubt. Thank you @Rajani. You have a teaching skills.
(1)
Sakthivasan said:
5 years ago
Please explain for me.
(1)
Alisha said:
9 years ago
I agree with you @Yash.
The present age of the son should be 20.
If not please explain.
The present age of the son should be 20.
If not please explain.
Durgadatta said:
9 years ago
Let son's age = x,
Father is 24 years elder than the son, hence son's age = 24 + x,
In the question given that, after 2 years father age will be twice the age of the son.
So, (x + 24) + 2 = 2(x + 2) solve this.
The answer is 22.
Father is 24 years elder than the son, hence son's age = 24 + x,
In the question given that, after 2 years father age will be twice the age of the son.
So, (x + 24) + 2 = 2(x + 2) solve this.
The answer is 22.
Mohd danish said:
9 years ago
Guys.
Because both father and son ages are increasing. If father age increases two years so sons are will be increased.
Because both father and son ages are increasing. If father age increases two years so sons are will be increased.
Lucky said:
9 years ago
@Alisha and Yash,
We assume that the present age of son be "x" that is 22. We don't subtract 2 from that.
We assume that the present age of son be "x" that is 22. We don't subtract 2 from that.
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