Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 6)
6.
A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
Answer: Option
Explanation:
Let the son's present age be x years. Then, man's present age = (x + 24) years.
(x + 24) + 2 = 2(x + 2)
x + 26 = 2x + 4
x = 22.
Discussion:
94 comments Page 10 of 10.
Deepak Lohani said:
1 decade ago
In question it is clearly said that man's age will be twice the age of his son. So we have added 2 on both sides i.e. X+24+2 and X+2, where we have multipied by 2 on son's age to make equation equal. Have you clear friends ?
Shilpa said:
1 decade ago
Son age=x
Father age=x+24
After 2 years father age will be twice than son age
There fore x+24+2=26+x---------->1
Son age after 2yrs (x+2)2------->2
Sub 1 n 2
x+26=4+2x
2x-x=26-4
x=22
Father age=x+24
After 2 years father age will be twice than son age
There fore x+24+2=26+x---------->1
Son age after 2yrs (x+2)2------->2
Sub 1 n 2
x+26=4+2x
2x-x=26-4
x=22
Hemant said:
1 decade ago
Did not understood please explain why we add 2 for fathers age and multiply two for son's age in the equation: (X+24) +2= (x+2) 2.
Bhavvi said:
1 decade ago
Thanks ranjani.
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