Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 4)
4.
A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?
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Answer: Option
Explanation:

Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.

(2x + 2) + 2x + x = 27

5x = 25

x = 5.

Hence, B's age = 2x = 10 years.

Discussion:
79 comments Page 5 of 8.

Vinayak said:   10 years ago
A = B+2.

C = 2B.

A+B+C = 27.

B+2+B++2B = 27.

4B = 25.

B = 6.25.

I got this. :).

V!cky said:   10 years ago
A+B+C = 27.

C is x.
B is 2x.

A is 2x + 2.

5x+2=27.
5x = 25.
x = 5.

GOWTHAMI said:   1 decade ago
Anyone answer me why we are not getting the answer if we substitute b=x?

Al1cee said:   1 decade ago
A+B+C = 27.

Let A = B-2.
B = It self.
C = 2B (B is twice older than C).

Substituting the givens A+B+C.

B-2+B+2B = 27.
4B = 27+2.
B = 29/4.
B = 7.

Anuj rojlove said:   1 decade ago
Friends this question solve easy trick.

Lets start assume.

C = x.

Then A = 2+B.
But B = 2C {its twice of C}.

So B = 2x {C = x (assume)}.

Now question.

A+B+C = 27.

(2+2x)+2x+x = 27.
= 2+5x = 27.
= 5x = 27-2.
= 5x = 25.
x = 5.

Then B = 2x (how old B).
B = 2*5.
B = 10 (answer).

Thiru said:   1 decade ago
Hi,

As per the question a+b+c=27, here a= b as of now reduced two years from b. So here b=a+2 years, c value is twice value of b, so which mean b*2.

Puranjan Sahu said:   1 decade ago
Hi,

You are telling A+B+C=27.

And your answer of B's age is 10.

Then how can you calculate the total age of all child as per your question suppose A=8, B=10 & C=12 then the total is 8+10+12=30.

Manoj said:   1 decade ago
Is there any shortcut method to solve question in examination hall?

Karan vekariya said:   1 decade ago
Here, b = 2c and a = (b-2) then,
(b-2)+b+b/2 = 27.

=>5b = 50.
So, b = 10.

Priya said:   1 decade ago
How come the age of A is 2X+2 years?


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